the two process that occur in a cell are
oxidation: this is loss of electron by electrode. the metal electrode loaes electrons and get oxidized and forms ions
the ions get migrated to solution
Reduction: here the ions present in solution gains electron and get deposited on electrodes.
so gain of electrons is by ions
electrode gains electrons is where reduction occurs, and the half cell in which the electrode loses electrons is where oxidation occurs.
Answer:
–1
Explanation:
The electronic configuration of the neutral atom is given below:
2 8 7
From the electronic configuration of the neutral atom, we can see that the atom has 7 electrons in it's outermost shell. This implies that the element needs 1 more electron to complete it's octet configuration.
Therefore the charge on the ion of the element will be –1 indicating that the atom has received 1 electron to complete it's octet configuration.
Answer:
1) 5 protons, 2) 5, 3) boron, 4) 6 Neutrons, 5) 10.811 ≈ 11, 6) Boron-9
Answer:
1.146 x 10⁴ year.
Explanation:
- The decay of carbon-14 is a first order reaction.
- The rate constant of the reaction (k) in a first order reaction = ln (2)/half-life = 0.693/(5730 year) = 1.21 x 10⁻⁴ year⁻¹.
- The integration law of a first order reaction is:
<em>kt = ln [A₀]/[A]</em>
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k is the rate constant = 1.21 x 10⁻⁴ year⁻¹.
t is the time = ??? years.
[A₀] is the initial percentage of carbon-14 = 100.0 %.
[A] is the remaining percentage of carbon-14 = 1/4[A₀] = 25.0 %.
∵ kt = ln [Ao]/[A]
∴ (1.21 x 10⁻⁴ year⁻¹)(t) = ln (100.0%)/[25.0 %]
(1.21 x 10⁻⁴ year⁻¹)(t) = 1.386.
∴ <em>t </em>= 1.386/
(1.21 x 10⁻⁴ year⁻¹) = <em>1.146 x 10⁴ year.</em>
