The given
ketone when reacted with base gave
enolate, the enolate formed due to loss of
methylene proton next to carbonyl group. Enolate when treated with
methyle Bromide gave
alpha substituted product.
Strong absorption around 1713 cm⁻¹ in IR spectrum confirms the presence of
Carbonyl group.
The product along with
¹H-NMR values is given below,
Answer:
Carbon dioxide is a product (cellular respiration)
Carbon dioxide is a reactant(photosynthesis)
Carried out in animals(cellular respiration)
Carried out in plants(both)
Chemical reaction(cellular respiration)
Oxygen is a product(photosynthesis)
Oxygen is a reactant(cellular respiration)
Produces usable energy source(photosynthesis)
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A. There is no movement
Hope this helps
Answer:
should be B
because the player has more mass than the puck
Explanation:
Answer:
A. 2C + H₂ ⟶ CH₄
Explanation:
A. 2C + H₂ ⟶ CH₄
UNBALANCED. 2C on the left and 1C on the right
B. 2Al₂O₃ ⟶ 4Al + 3O₂
Balanced. Same number of each type of atom on each side.
C. 2H₂O₂ ⟶ 2H₂O + O₂
Balanced. Same number of each type of atom on each side.
D. 2C₂H₆ + 7O₂ ⟶ 4CO₂ + 6H₂O
Balanced. Same number of each type of atom on each side.
