Answer:
The minimum molarity of acetic acid in vinegar according to given standards is 0.6660 mol/L.
Explanation:
4% acetic acid by mass means that 4 gram of acetic acid in 100 g solution.
Given that density of the vinegar is same is that of water = 1 g/mL
Mass of the vinegar solution = 100 g
Volume of the vinegar solution = V


V = 100 mL = 0.1 L
Moles of acetic acid =


The minimum molarity of acetic acid in vinegar according to given standards is 0.6660 mol/L.
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