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Rus_ich [418]
2 years ago
7

The PV system is operating in a location where the annual average daily incident solar energy (the insolation) on the array equa

ls 200 kWh/m2/day. Calculate the average amount of solar energy incident on the PV array each day in kWh/day.
Physics
1 answer:
vlabodo [156]2 years ago
5 0

The average amount of solar energy incident on the PV per day is 10000 kWh/day.

<h3>Equation</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Let the PV array has an area equal to 50 square meters. Hence:

Average amount of solar energy incident on the PV per day = 200 kWh/m²/day * 50 m² = 10000 kWh/day.

Find out more on Equation at: brainly.com/question/2972832

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A wheel of diameter 8.0 cm has a cord of length 6.0 m wound around its periphery. Starting from rest, the wheel is given a const
MAVERICK [17]

Answer: time t = 10s

Explanation:

Given;

Diameter = 8.0cm = 0.08m

Radius r = diameter/2 = 0.08/2 = 0.04m

Cord length d = 6.0m

Angular acceleration = 3.0rads/s2

Time = t

Converting the angular acceleration to linear acceleration

a = a* × r = 3.0 × 0.04 = 0.12m/s

d = vt + 1/2 (a × t^2)

Initial velocity v = 0, vt = 0 therefore;

d = 1/2 ( a × t^2)

t = √(2d/a)

t = √ [(2× 6)/0.12]

t = 10s

6 0
3 years ago
A horse running at 3 m/s speeds up with a constant acceleration of 5 m/s2. How fast is the
Elan Coil [88]

Answer:

The horse is going at 12.72 m/s speed.

Explanation:

The initial speed of the horse (u) = 3 m/s

The acceleration of the horse (a)= 5 m/s^{2}

The displacement( it is assumed it is moving in a straight line)(s)= 15.3 m

Applying the second equation of motion to find out the time,

s=ut+\frac{1}{2}at^{2}

15.3=3t+2.5t^{2}

2.5t^{2}+3t-15.3=0

Solving this quadratic equation, we get time(t)=1.945 s, the other negative time is neglected.

Now applying first equation of motion, to find out the final velocity,

v=u+at

v=3+1.945*5

v=3+9.72

v=12.72 m/s

The horse travels at a speed of 12.72 m/s after covering the given distance.

7 0
4 years ago
Why do electric field lines explain why like charges repel and opposite charges attract?
vivado [14]

It can be explained as follows: consider the field produced by a positive charge. If we place a positive test charge in this a field, then this charge would move away from the central charge (because like charges repel), while if we place a negative test charge in this field, this charge would move towards the central charge (because opposite charges repel)

Explanation:

Electric fields are vector fields, and they are represented using field lines.

The field lines give indications on both the magnitude and the direction of the electric field. In fact:

  • The magnitude of the field can be inferred from the spacing between the lines: the closer the lines are, the stronger the field, while for a weaker field the lines are more spread apart
  • The direction of the field is given by the direction of the field lines

In particular, by convention the direction of the field lines represent the direction of the force that a positive test charge would feel when immersed in that field: this means that a positive test charge would accelerate in the direction of the field lines, while a negative test charge would accelerate in the direction opposite to the field lines.

This is in agreement with the fact that like charges repel and opposite charges attract. In fact, the lines of the electric field produced by a single-point positive charge point away from the positive charge: if we place a positive test charge in this field, then this charge would move away from the central charge (because like charges repel), while if we place a negative test charge in this field, this charge would move towards the central charge (because opposite charges repel).

Learn more about electric fields:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

5 0
3 years ago
During a move, Jonas and Matías carry a 115kg safe to the third floor of a building, covering a height of 6.6m.
neonofarm [45]

Answer:

work is =7590joules

power = 23watts

4 0
3 years ago
Read 2 more answers
Lasers utilize concentrated light waves, focused precisely and used for certain applications. What are some common uses of laser
SVEN [57.7K]

its 1,3,4,5 just got it right on edge

5 0
3 years ago
Read 2 more answers
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