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Yuliya22 [10]
2 years ago
5

A thin slice of silicon that contains many solid-state components is a(an)

Physics
2 answers:
Tasya [4]2 years ago
8 0
It's an intrigated circuit
dangina [55]2 years ago
5 0

Answer:Intergrated circuit

Explanation:

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Can you describe Saturn?
Arte-miy333 [17]
<span>Saturn is the sixth planet from the Sun and the second-largest in the Solar System, after Jupiter. It is a gas giant with an average radius about nine times that of Earth.</span>
6 0
3 years ago
A 6,000N is applied to a formula one car that weighs 500kg. What is the car's acceleration?
Vesna [10]

Answer:

<h2>12 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question

f = 6000 N

m = 500 kg

We have

a =  \frac{6000}{500}  =  \frac{60}{5}  = 12 \\

We have the final answer as

<h3>12 m/s²</h3>

Hope this helps you

8 0
2 years ago
Help please:A boy weighing 30 kg rides a scooter. The total kinetic energy of the boy and the scooter is 437.6 J. Determine the
Ksenya-84 [330]

Answer:

the total mass is 35 kg

k.E = 1/2 mv2

43.76 =1/2 v2

v2=2×43.76

Explanation:

v=radicls 87.52 which is equal to 9.5 m/s

5 0
3 years ago
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Table is in the picture. and will mark brainstest.
QveST [7]
B. A copper wire with rubber insulation
8 0
2 years ago
A historical society is testing an old cannon. They
sveta [45]

Answer:

26.2 m/s

Explanation:

We can find the speed of the cannonball just by analyzing its vertical motion. In fact, the initial vertical velocity is

u_y = u sin \theta (1)

where u is the initial speed and \theta = 45.0^{\circ} is the angle of projection.

We can therefore use the following suvat equation for the vertical motion of the ball:

v_y = u_y + at

where v_y is the vertical velocity at time t, and a=g=-9.8 m/s^2 is the acceleration of gravity. The time of flight is 3.78 s, so we know that the ball reaches its maximum height at half this time:

t=\frac{3.78}{2}=1.89 s

And at the maximum height, the vertical velocity is zero:

v_y=0

Substituting these values, we find the initial vertical velocity:

u_y = v_y - at = 0-(-9.8)(1.89)=18.5 m/s

And using eq.(1) we now find the initial speed:

u=\frac{u_y}{sin \theta}=\frac{18.5}{sin 45.0^{\circ}}=26.2 m/s

4 0
2 years ago
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