Explanation:
Because the temperature and the radiation are not correlated, they're not represented as functions of each other, they're represented as independent variables thus using graph 5 you cannot figure out how one affect another
We are given the equation:
<span>x = 11t^2
</span>
We use that equation to calculate for the distance traveled.
For (a)
At t=2.20 sec,
x =53.24 meters
At t=2.95 sec,
x =95.73 meters
Velocity = (95.73 meters - 53.24<span> meters) / (2.95 s - 2.20 s ) = 56.65 m/s
</span>For (b)
At t=2.20 sec,
x =53.24 meters
At t=2.40 sec,
x =63.36 meters
Velocity = (63.36 meters - 53.24<span> meters) / (2.40 s - 2.20 s ) = 50.6 m/s</span>
Answer: Tension = 47.8N, Δx = 11.5×
m.
Tension = 95.6N, Δx = 15.4×
m
Explanation: A speed of wave on a string under a tension force can be calculated as:
is tension force (N)
μ is linear density (kg/m)
Determining velocity:
0.0935 m/s
The displacement a pulse traveled in 1.23ms:
Δx = 11.5×
With tension of 47.8N, a pulse will travel Δx = 11.5× m.
Doubling Tension:
|v| = 0.1252 m/s
Displacement for same time:
15.4×
With doubled tension, it travels 15.4× m
The circular lines you see on the chart are isobars, which join areas of the same barometric pressure.
