This year is 60 years since I learned this stuff, and one of the things I always remembered is the formula for the distance a dropped object falls:
D = 1/2 A T²
Distance = (1/2) (acceleration) (time²)
The reason I never forgot it is because it's SO useful SO often. You really should memorize it. And don't bury it too deep in your toolbox ... you'll be needing it again very soon. (In fact, if you had learned it the first time you saw it, you could have solved this problem on your own today.)
The problem doesn't tell us what planet this is happening on, so let's make it easy and just assume it's on Earth. Then the 'acceleration' is Earth gravity, and that's 9.8 m/s² .
In 5 seconds:
D = 1/2 A T²
D = (1/2) (9.8 m/s²) (5 sec)²
D = (4.9 m/s²) (25 sec²)
D = 122.5 meters
In 6 seconds:
D = 1/2 A T²
D = (1/2) (9.8 m/s²) (6 sec)²
D = (4.9 m/s²) (36 sec²)
D = 176 meters
Answer:
A magnet is used in a compass to show the direction.
Magnets are used in medical equipment.
Powerful magnets are used to lift objects
they are used in refrigerator, televisions, earphones etc
Answer:
Pitcher is accelerating the ball at 30 times of acceleration due to gravity = 294 m/s²
Explanation:
Force applied on baseball = 30 times weight of the ball.
Weight of ball = mg, where m is the mass of ball and g is acceleration due to gravity value.
We have force applied is also equal to product of mass and acceleration.
F = ma = 30 x mg
a = 30g
So, pitcher is accelerating the ball at 30 times of acceleration due to gravity = 294 m/s²
Answer:
a) 1504.8 J
b) 991.76 J
c) 0J
d) 0J
Explanation:
(a) The work done by the force P on the box is given by the following formula:
P: applied force = 171N
x: distance in which the for P is applied = 8.80m
you replace the values of P and x and obtain:
(b) The work don by the friction force is:
μ = coefficient of kinetic friction = 0.250
M: mass of the box = 46.0kg
g: gravitational constant = 9.8 m/s^2
(c) The Normal force is
but this force does not do work on the box because the direction is perpendicular to the direction of the force P.
(d) the same as before:
Answer:
The following options are true based on the properties of electric field;
a) Electric field lines near positive point charges radiate outward.
b) The electric force acting on a point charge is proportional to the magnitude of the point charge.
d) In a uniform electric field, the field lines are straight, parallel, and uniformly spaced.
Explanation:
From option b) From coulomb's law F = Kq1q2r/r2
