Ask question

Ask question

All categories

3 years ago

13

Scott cuts a one meter long wire into five equal parts. What is the length of each part of the wire? (2 points) 0.02 centimeters

0.20 centimeters 20 centimeters 200 centimeters

2 answers:

OlgaM077 [116]3 years ago

8 0

Answer: The length of each part of the wire 20 centimeter.

Explanation:

Length of the wire = 1 m

On dissecting the 1 meter wire into equal five parts = $\frac{1 m}{5}$

The length of the each part will be = $\frac{1 m}{5}=0.2 m$

1 meter = 100 centimeter

So, 0.2 meter = $0.2\times 100 centimeter=20 centimeter$

The length of each part of the wire 20 centimeter.

kompoz [17]3 years ago

4 0

20 centimeters. 100 centimeters in a meter. 100/5= 20

You might be interested in

A solid disk of mass 2 kg and radius 2 m is given a horizontal push of 20N at a point .3 m above its center. a. What is the mini

Margaret [11]

Answer:

$\mu_s=1.0205$

Explanation:

Given:

mass of solid disk, $m=2\ kg$

radius of disk, $r=2\ m$

force of push applied to disk, $F=20\ N$

distance of application of force from the center, $s=0.3\ m$

<em>For the condition of no slip the force of static friction must be greater than the applied force so that there is no skidding between the contact surfaces at the contact point.</em>

$\therefore F$

where:

$f_s$ = static frictional force

$\Rightarrow 20$

$\Rightarrow 20$

$\Rightarrow 20$

$\mu_s>1.0204$

7 0

3 years ago

A crane raises a crate with a mass of 150 kg to a height of 20 m. Given that

Virty [35]

Answer:

$\boxed {\boxed {\sf 29,400 \ Joules}}$

Explanation:

Gravitational potential energy is the energy an object possesses due to its position. It is the product of mass, height, and acceleration due to gravity.

$E_P= m \times g \times h$

The object has a mass of 150 kilograms and is raised to a height of 20 meters. Since this is on Earth, the acceleration due to gravity is 9.8 meters per square second.

m= 150 kg
g= 9.8 m/s²
h= 20 m

Substitute the values into the formula.

$E_p= 150 \ kg \times 9.8 \ m/s^2 \times 20 \ m$

Multiply the three numbers and their units together.

$E_p=1470 \ kg*m/s^2 \times 20 m$

$E_p=29400 \ kg*m^2/s^2$

Convert the units.

1 kilogram meter square per second squared (1 kg *m²/s²) is equal to 1 Joule (J). Our answer of 29,400 kg*m²/s² is equal to 29,400 Joules.

$E_p= 29,400 \ J$

The crate has <u>29,400 Joules</u> of potential energy.

7 0

3 years ago

What does Newton's third law describe?<br> What does Newton's third law describe?

defon

Explanation:

<em>Sir Isaac Newton's third law of motion</em> says that every action has an equal and opposite reaction.

For example, when you fire a gun, the gun exerts a force on bullet. Even the bullet exerts an equal force on the gun, causing it to recoil.

The Earth revolves around the Sun as the Sun attracts it. The reason why Earth doesn't fall into it is because the Earth also attracts the Sun with an equal gravitational force.

4 0

3 years ago

Two vectors, X and Y, form a right angle. Vector X is 48 inches long and vector Yis 14 inches long. The length of

Troyanec [42]

48 inches go restaurant vector is 14 inches Long and right angle

6 0

3 years ago

An 80- kg quarterback jumps straight up in the air right before throwing a 0.43-kg football horizontally at 15m/s . Sort the fol

torisob [31]

Answer:

1. The mass of the quarterback = known = 80 kg

2. The mass of the football = known = 0.43 kg

3. The horizontal velocity of quarterback before throwing the ball = known = 0

4. The horizontal velocity of football before being thrown = known = 0

5. The horizontal velocity of quarterback after throwing the ball, = unknown quantity and it can be calculated using the conservation of linear momentum.

6. The horizontal velocity of football after being thrown = known = 15 m/s

Explanation:

Given that,

Mass of the quarterback, m = 80 kg

Mass of the football, m' = 0.43 kg

Speed of the football, v' = 15 m/s

We need to sort the following quantities as known or unknown.

1. The mass of the quarterback = known = 80 kg

2. The mass of the football = known = 0.43 kg

3. The horizontal velocity of quarterback before throwing the ball = known = 0

4. The horizontal velocity of football before being thrown = known = 0

5. The horizontal velocity of quarterback after throwing the ball, = unknown quantity and it can be calculated using the conservation of linear momentum.

6. The horizontal velocity of football after being thrown = known = 15 m/s

6 0

3 years ago

Read 2 more answers