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gavmur [86]
2 years ago
13

Scott cuts a one meter long wire into five equal parts. What is the length of each part of the wire? (2 points) 0.02 centimeters

0.20 centimeters 20 centimeters 200 centimeters
Physics
2 answers:
OlgaM077 [116]2 years ago
8 0

Answer: The length of each part of the wire 20 centimeter.

Explanation:

Length of the wire =  1 m

On dissecting the 1 meter wire into equal five parts =\frac{1 m}{5}

The length of the each part will be =\frac{1 m}{5}=0.2 m

1 meter = 100 centimeter

So, 0.2 meter = 0.2\times 100 centimeter=20 centimeter

The length of each part of the wire 20 centimeter.

kompoz [17]2 years ago
4 0
20 centimeters. 100 centimeters in a meter. 100/5= 20
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The new speed of car is 10.9 m/s

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According to the principle of momentum conservation, momentum is only modified by the action of forces as they are outlined by Newton's equations of motion; momentum is never created nor destroyed inside a problem domain.

Mass of the railroad car, m₁ = 7950 kg

Mass of the load, m₂ = 2950 kg

It can be assumed as the speed of the car, u₁ = 15 m/s

Initially, it is at rest, u₂ = 0

Let v is the speed of the car. It can be calculated using the conservation of momentum as :

m_1u_1 + m_2u_2 = (m_1 + m_2) v

v =\frac{m_1u_1}{m_1+m_2}

v = \frac{7950*15}{7950+2950}

v= 10.9 m/s

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5 0
2 years ago
A 235 kg crate is pulled across a horizontal surface with a force of 760 N applied at an
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Answer:

658.16N

Explanation:

Step one:

given data

mass m= 235kg

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angle= 30 degrees

Required

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Fh= 760cos∅

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2 years ago
A body is thrown up with a velocity of 78.4 m per second.How high will it rise and how much time it will take to return to its p
a_sh-v [17]

Answer:

The maximum height reached by the body is 313.6 m

The time to return to its point of projection is 8 s.

Explanation:

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The following equation is applied to determine the maximum height reached by the body;

v² = u² - 2gh

0 = u² - 2gh

2gh = u²

h = u²/2g

h = (78.4²) / (2 x 9.8)

h = 313.6 m

The time to return to its point of projection is calculated as follows;

at maximum height, the final velocity becomes the initial velocity = 0

h = v + ¹/₂gt²

h = 0 + ¹/₂gt²

h =  ¹/₂gt²

2h = gt²

t² = 2h/g

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2 years ago
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The car A has a mass of 1200 kg.

The car B has the mass of 1900 kg.

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[Here p stand for momentum.]

We are asked to calculate the final momentum of the system after collision.

The answer of the question is based law of conservation of  linear momentum.

As per law of conservation of linear momentum the sum total linear momentum for an isolated system is always constant.Hence irrespective of the type of collision[elastic and inelastic],the momentum of the system is always constant which is a universal truth.

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As per the law of conservation of linear momentum, the initial and final momentum must be equal i.e      

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