Is this chemical equation balanced? Yes or no
2 answers:
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Answer : (C) Hafnium is the most likely identity of the given substance.
Solution : Given,
Mass of given substance (m) = 46.9 g
Volume of given substance (V) = 3.5
First, find the Density of given substance.
Formula used :
Now,put all the values in this formula, we get
= 13.4 g/
So, we conclude that the density of given substance (13.4 g/) is approximately equal to the density of Mercury and Hafnium (13.53 and 13.31 g/
respectively).
According to the question the substance is solid at room temperature but Mercury is liquid at room temperature. So, Mercury is not identical to the given substance.
Another element i.e, Hafnium is the element whose density is approximately equal to the given substance and also solid at room temperature. And we know that the melting point of solid is high.
So, Hafnium is the most likely element which is the identity of the given substance.
Answer : The equilibrium concentration of in the trial solution is
Explanation :
First we have to calculate the initial moles of and
.
and,
The given balanced chemical reaction is,
Since 1 mole of reacts with 1 mole of
to give 1 mole of
The limiting reagent is,
So, the number of moles of = 0.0020 mmole
Now we have to calculate the concentration of .
Using Beer-Lambert's law :
where,
A = absorbance of solution
C = concentration of solution
l = path length
= molar absorptivity coefficient
and l are same for stock solution and dilute solution. So,
For trial solution:
The equilibrium concentration of is,
= 0.00050 M
Now calculate the .
Now calculate the concentration of .
Therefore, the equilibrium concentration of in the trial solution is