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2 years ago

What is the molarity of a solution that has 26 moles of nacl in 2. 7 l of water?.

Chemistry

1 answer:

VikaD [51]2 years ago

7 0

The molarity of a solution that has 26 moles of NaCl in 2.7L of water is 9.63M.

<h3>How to calculate molarity?</h3>

The molarity of a solution can be calculated by dividing the number of moles of the solute by the volume of the solution as follows:

Molarity = no of moles ÷ volume

According to this question, a solution has 26 moles of NaCl in 2. 7 l of water. The molarity is as follows:

Molarity = 26mol ÷ 2.7L

Molarity = 9.6M.

Therefore, the molarity of a solution that has 26 moles of NaCl in 2.7L of water is 9.63M.

Learn more about molarity at: brainly.com/question/2817451

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Answer:

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$m_mc_m\Delta T_m=m_wc_w\Delta T_w\\\Rightarrow c_m=\dfrac{m_wc_w\Delta T_w}{m_m\Delta T_m}\\\Rightarrow c_m=\dfrac{150\times 4.186\times 2}{19\times 76}\\\Rightarrow c_m=0.8696\ \text{J/g}^{\circ}\text{C}$

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