All categories

2 years ago

What is the molarity of a solution that has 26 moles of nacl in 2. 7 l of water?.

Chemistry

1 answer:

VikaD [51]2 years ago

7 0

The molarity of a solution that has 26 moles of NaCl in 2.7L of water is 9.63M.

<h3>How to calculate molarity?</h3>

The molarity of a solution can be calculated by dividing the number of moles of the solute by the volume of the solution as follows:

Molarity = no of moles ÷ volume

According to this question, a solution has 26 moles of NaCl in 2. 7 l of water. The molarity is as follows:

Molarity = 26mol ÷ 2.7L

Molarity = 9.6M.

Therefore, the molarity of a solution that has 26 moles of NaCl in 2.7L of water is 9.63M.

Learn more about molarity at: brainly.com/question/2817451

You might be interested in

"11. Barium nitrate reacts with aqueous sodium sulfate to produce solid barium sulfate and aqueous sodium nitrate. Abigail place

Amanda [17]

Answer:

44 mL of Na2SO4

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

Ba(NO3)2 (aq) + Na2SO4 (aq) —> BaSO4 (s) + 2NaNO3 (aq)

Step 2:

Determination of the number of mole of Ba(NO3)2 in 20.00 mL of 0.500 M barium nitrate (Ba(NO3)2). This is illustrated below:

Molarity of Ba(NO3)2 = 0.5 M

Volume of solution = 20 mL = 20/1000 = 0.02 L

Mole of solute (Ba(NO3)2) =?

Molarity = mole /Volume

0.5 = Mole of Ba(NO3)2 / 0.02

Cross multiply to express in linear form

Mole of Ba(NO3)2 = 0.5 x 0.02

Mole of Ba(NO3)2 = 0.01 mole

Step 3:

Determination of the number of mole of Na2SO4 that reacted.

Ba(NO3)2 (aq) + Na2SO4 (aq) —> BaSO4 (s) + 2NaNO3 (aq)

From the balanced equation above,

1 mole of Ba(NO3)2 reacted with 1 mole of Na2SO4.

Therefore, 0.01 mole of Ba(NO3)2 will also react with 0.01 mole of Na2SO4.

Step 4:

Determination of the volume of Na2SO4 needed for the reaction. This is illustrated below:

Mole of Na2SO4 = 0.01 mole

Molarity of Na2SO4 = 0.225M

Volume =?

Molarity = mole /Volume

0.225 = 0.01 / volume

Cross multiply to express in linear form

0.225 x Volume = 0.01

Divide both side by 0.225

Volume = 0.01/0.225

Volume of Na2SO4 = 0.044 L

Converting 0.044 L to mL, we have

Volume of Na2SO4 = 0.044 x 1000

Volume of Na2SO4 = 44 mL

Therefore, 44 mL of Na2SO4 is needed for the reaction

6 0

4 years ago

Read 2 more answers

Which of these elements exhibits chemical behavior similar to that of oxygen? select one:

scoray [572]

Answer:
Sulfur (Option-C) <span>exhibits chemical behavior similar to that of oxygen.

Explanation:
Sulfur has same chemical properties as that of Oxygen because both of them belongs to same group in the periodic table. Also, the similarity of chemical behaviour among the group members is due to same number of electrons in their valence shells.
For examole, the electronic configuration of Oxygen is,

1s</span>², 2s², 2p⁴

There are six valence electrons in the valence shell (i.e. 2) of Oxygen.

Now for Sulfur,
1s², 2s², 2p⁶, 3s², 3p⁴

There are six valence electrons in the valence shell (i.e. 3) of Sulfur.

Therefore, both elements tends to gain 2 electrons in a reaction and form O⁻² and S⁻² respectively.

3 0

4 years ago

Question 7 of 10

nirvana33 [79]

Answer:

I think the answer is D. Temperature affects only the rate of reaction.

7 0

3 years ago

At 7 degrees Celsius the volume of gas is 49 liters. At the same pressure its volume is 74 mL at what temperature

Romashka-Z-Leto [24]

Charle's law gives the relationship between volume and temperature of gas.
It states that at constant pressure, volume of gas is directly proportional to temperature of gas.
V/T = k
where V - volume , T - temperature and k- constant
$\frac{V1}{T1} = \frac{V2}{T2}$
parameters for the first instance are on the left side of the equation and parameters for the second instance are on the right side of the equation
T1 - 7 °C + 273 = 280 K
substituting these values in the equation
$\frac{49 mL}{280K} = \frac{74 mL}{T}$
T = 423 K
temperature in Celcius scale - 423 K - 273 = 150 °C

4 0

4 years ago

Which statement is correct about the conclusions of historical events? A) Historical event conclusions can be tested using the s

BARSIC [14]

C is the correct answer I believe

4 0

3 years ago

Read 2 more answers