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3 years ago

1. The mass of 6.45 x 1022 atoms C

Chemistry

1 answer:

Fed [463]3 years ago

7 0

Answer:

$\large \boxed{\text{1.29 g}}$

Explanation:

We must convert atoms of C to moles of C and then to grams of C.

1. Convert atoms to moles

$\text{Moles of C} = 6.45 \times10^{22}\text{ atoms C} \times \dfrac{\text{1 mol C}}{6.022 \times\ 10^{23} \text{ atoms C}} = \text{0.1071 mol C}$

2. Convert moles to grams

$\text{Mass of C} = \text{0.1071 mol C} \times \dfrac{\text{12.01 g C}}{\text{1 mol C}} = \text{1.29 g C}\\\text{The mass of C is $\large \boxed{\textbf{1.29 g}}$}$

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Explanation:

Our strategy here is to use the definition of molarity and molality to solve this question.

The molarity is the number of moles of solute, sucrose in this case, per liter of solution.

The molality is the number of moles of solute per kilogram of solvent.

So the molarity of the solution is

M = moles of solute/ V solution

As we see we need the volume of solution since we are only given the volume of solvent, but this will be easy to compute since we have the density of sucrose.

So determine the moles of sucrose , and the volume of solution:

Moles sucrose = 1.11 g/342.3 g/mol = 3.24 x 10⁻³ M

Volume of solution = Vol Sucrose + Vol glycerine

d = m/V ⇒ Vsucrose = m / d = 1.11 g/ 1.587 g/cm³ = 0.70 cm³

Vol solution = 432 mL + 0.70 mL = 432.7 mL (1cm³ = 1 mL)

Vol solution = 432.7 mL x 1 L / 1000 mL = 0.4327 L

⇒ M = 3.2 x 10⁻³ mol / 0.4327 L = 0.0075 M

For the molarity what we need is to first calculate the kilograms of glycerine from the given density:

d = m/v ⇒ m = d x v = 1.261 g/cm³ x 432 cm³ = 544.75 g

Converting to Kg:

544.75 g x 1 Kg/ 1000 g = 0.544 kg

Now the molality is

m = mol sucrose/ kg solvent = 3.24 x 10⁻³ mol / 0.544 Kg = 0.0060 m

Note: In the calculation for volume of solution we could have approximated it to that of just glycerine, but since the density of sucrose was given we calculated the total volume of solution to be more rigorous.

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3 years ago

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Nutka1998 [239]

Answer: The ionic compound formed is magnesium chloride having formula $MgCl_2$

Explanation:

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The atom which looses the electron is known as electropositive atom and the atom which gains the electron is known as electronegative atom. This bond is usually formed between a metal and a non-metal.

Magnesium is the 12th element of the periodic table having electronic configuration of $1s^22s^22p^63s^2$

This element will loose 2 electrons to form $Mg^{2+}$ ion

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This element will gain 1 electron to form $Cl^{-}$ ion

So, for every 1 atom of magnesium, 2 atoms of chlorine are required. Thus, the chemical formula becomes $MgCl_2$

Hence, the ionic compound formed is magnesium chloride having formula $MgCl_2$

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1. The mass of 6.45 x 1022 atoms C​

1. The mass of 6.45 x 1022 atoms C