The molar mass of the gas : 18 x 10⁻³ kg/mol
<h3>Further explanation</h3>
Given
An unknown gas has one third the root mean square speed of H2 at 300 K
Required
the molar mass of the gas
Solution
Average velocities of gases can be expressed as root-mean-square (V rms)
![\large {\boxed {\bold {v_ {rms} = \sqrt {\dfrac {3RT} {Mm}}}}](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7B%5Cbold%20%7Bv_%20%7Brms%7D%20%3D%20%5Csqrt%20%7B%5Cdfrac%20%7B3RT%7D%20%7BMm%7D%7D%7D%7D)
T = temperature, Mm = molar mass of the gas particles , kg/mol
R = gas constant 8,314 J / mol K
v rms An unknown gas = 1/3 v rms H₂
v rms H₂ :
![\tt v_{rms}=\sqrt{\dfrac{3\times 8.314\times 300}{2.10^{-3}} }\\\\v_{rms}=1934.22](https://tex.z-dn.net/?f=%5Ctt%20v_%7Brms%7D%3D%5Csqrt%7B%5Cdfrac%7B3%5Ctimes%208.314%5Ctimes%20300%7D%7B2.10%5E%7B-3%7D%7D%20%7D%5C%5C%5C%5Cv_%7Brms%7D%3D1934.22)
V rms of unknown gas =
![\tt \dfrac{1}{3}\times 1934.22=644.74](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B1%7D%7B3%7D%5Ctimes%201934.22%3D644.74)
![\tt 644.74^2=\dfrac{3\times 8.314\times 300}{M_{gas}}\\\\M_{gas}=18\times 10^{-3}~kg/mol](https://tex.z-dn.net/?f=%5Ctt%20644.74%5E2%3D%5Cdfrac%7B3%5Ctimes%208.314%5Ctimes%20300%7D%7BM_%7Bgas%7D%7D%5C%5C%5C%5CM_%7Bgas%7D%3D18%5Ctimes%2010%5E%7B-3%7D~kg%2Fmol)
The apparent topography exhibited by minerals in thin section as a consequence of refractive index.
Answer:
The common ion will be di-positive ion.
Explanation:
The ionization energy is defined as the amount of energy needed for removal of most loosely bound electron from an isolated atom in gaseous state.
The low ionization energy shows that the atom is able to give electron easily as after losing electron it may attain noble gas configuration or half filled stability.
Here the first and second ionization energy, both are low suggesting that the element is ready to give two electrons easily to form a di-positive ion however the third ionization energy is high which shows that it will not form tri-positive ion commonly.
Explanation:
Since, it is shown that the reaction has been reversed. Therefore, value of
will become
.
Hence, new ![K_{c'} = \frac{1}{K_{c}}](https://tex.z-dn.net/?f=K_%7Bc%27%7D%20%3D%20%5Cfrac%7B1%7D%7BK_%7Bc%7D%7D)
= ![\frac{1}{0.0500}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B0.0500%7D)
= 20
Also, the number of moles of each reactant has been halved. So,
for the reaction
will also get halved.
Therefore,
=
= ![(20)^{0.5}](https://tex.z-dn.net/?f=%2820%29%5E%7B0.5%7D)
= 4.47
As the value of
is given as +39.0 kJ. So, it means that the reaction is endothermic in nature. So, energy of reactants will be more than the products. Hence, according to Le Chatelier's principle reaction will move in the forward direction.
As a result,
will also increase with increase in temperature.
B
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Sorry I need 20 characters to submit this Answer that’s why I’m adding more words