To yield an alcohol from an alkane, one reaction could be from alkyl halide through hydrolysis reaction. The alkyl halide should be pentyl chloride. When you add water to it, the OH⁻ ion will replace Cl to make 1-pentanol, while the Cl⁻ ion binds with H⁺ to form HCl. The main product is pentanol, while the by-product is HCl.
The reduction of alkyne to an alkene in the first step allows the best reagent to be chosen for each subsequent step.
Describe reagents.
A reagent is merely an essential component of a chemical reaction, it should be mentioned. It is an ingredient that speeds up the reaction.
With H2 and Lindlar's catalyst, an alkyne is reduced to alkene as the initial step in this process. Alkene will then be brominated to produce allyl bromide as the next step.
In this instance, the required allyl alcohol will be produced via the reaction of allyl bromide with NaOH.
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Answer:
D
Explanation:
The high jump of ionization energy indicates that we are trying to remove electron from noble gas configuration state.
The ionization energy data specifies that the Elements are from group 1 at period 3 or greater.
Removing the first electron require 496 kJ and the second ionization energy jump significantly due to the removal of electron from the noble gas configuration which is logical because electron try to maintain the especially stable state.
