Answer:
Mass of Ca(OH)₂ required = 0.09 g
Explanation:
Given data:
Volume of HNO₃ = 25 mL (25/1000 = 0.025 L)
Molarity of HNO₃ = 0.100 M
Mass of Ca(OH)₂ required = ?
Solution:
Chemical equation;
Ca(OH)₂ + 2HNO₃ → Ca(NO)₃ + 2H₂O
Number of moles of HNO₃:
Molarity = number of moles / volume in L
0.100 M = number of moles / 0.025 L
Number of moles = 0.100 M ×0.025 L
Number of moles = 0.0025 mol
Now we will compare the moles of Ca(OH)₂ with HNO₃ from balance chemical equation.
HNO₃ : Ca(OH)₂
2 : 1
0.0025 : 1/2×0.0025 = 0.00125
Mass of Ca(OH)₂:
Mass = number of moles × molar mass
Mass = 0.00125 mol × 74.1 g/mol
Mass = 0.09 g
This method relies on the exothermic reaction of lithium hydroxide with carbon dioxide gas to create lithium carbonate (Li2CO3) solid and water (H2O).
might be wrong but....oh well
When we have this equation:
CO(g) + Cl2(g) ↔ COCl2(g)
intial 0.147 0.175 0
change -X -X +X
final (0.147-X) (0.175-X) X
so from the ICE table, we substitute in Kc formula :(when we have Kc = 255)
Kc = [COCl2]/[CO][Cl2]
255= X / (0.147-X)(0.175-X)
255 = X / (X^2 - 0.322 X + 0.025725)
X = 0.13
∴[CO] = 0.147 - X = 0.147 - 0.13
= 0.017 m
Answer:
After 4 days 10 g will left
After 8 days 5 g will left.
Explanation:
Given data:
Half life of isotope = 4 days
Total amount of sample = 20 g
Amount left after each time period = ?
Solution:
The half life of radioactive isotope is 4 days it means after 4 days the amount left will be half of total amount.
20 g/2 = 10 g
The half amount which is left will be consume in next 4 days and remaining amount will be,
10 g/2 = 5 g
After 4 days 10 g will left
After 8 days 5 g will left.
Answer:
Ammonium,
N
H
+
4
Explanation:
Conjugate acid-base pairs consist of two compounds, differing by a charge of +/-1 due to the movement of a single proton
H
+
You use the bronstead description of acids and bases when calculating which is the conjugate acid and which is the conjugate base in a reaction. This theory explains that a bronstead acid is any molecule, ion or atom that can donate a proton and a bronstead base is any molecule, ion or atom that can accept a proton.
In this reaction, ammonia is the conjugate base and accepts a proton from water, where it becomes the conjugate acid ammonium. You can show that the lone pair of electrons on the nitrogen atom reacts with the hydrogen on water molecules, giving an ammonium ion and a hydroxide ion.
