Question

A candy-filled piñata is hung from a tree for Matthew's birthday. During an unsuccessful attempt to break the 4.4-kg piñata, Hayden cracks it with a 0.54-kg stick moving at 4.8 m/s. The stick stops and the piñata undergoes a gentle swinging motion. Determine the swing speed of the piñata immediately after being cracked by the stick.

Answer 1

Answer:

The speed of the piñata immediately after being cracked by the stick is $v_{fp}=0.59\: m/s$.

Explanation:

Using the conservation of linear momentum:

$m_{s}v_{is}=m_{p}v_{fp}$ (1)

Here:

m(s) is the mass of the stick

m(p) is the mass of the piñata

v(is) is the initial velocity of the stick

v(fp) is the final velocity of the piñata        

So, we just need to solve the equation (1) to v(fp).

$v_{fp}=\frac{m_{s}v_{is}}{m_{p}}$

$v_{fp}=\frac{0.54*4.8}{4.4}$

$v_{fp}=0.59\: m/s$

I hope it helps you!