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anastassius [24]
4 years ago
10

Which of the following is not a renewable resource

Chemistry
1 answer:
BabaBlast [244]4 years ago
4 0
Natural gas is nonrenewable, once its used you have to get more, after its all used up you cant use it no more.
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How many grams of silver are in 4.2 moles of silver?
Phantasy [73]

Answer:

Solution: Since the atomic mass of silver (Ag) is 107.87 amu, one mole of silver has a mass o f 107.87 grams. Therefore, there is one mole of Ag per 107.87 grams of Ag

Explanation:

8 0
3 years ago
If a gas has a volume of 3.67 L and a pressure of 790 mm Hg, what will the pressure be if the volume is compressed to 2.12 L? Wh
oksian1 [2.3K]

If each gas sample has the same temperature and pressure, which has the greatest volume? Since hydrogen gas has the lowest molar mass of the set, 1 g will have the greatest number of moles and therefore the greatest volume. What is the Ideal Gas Law?

7 0
3 years ago
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What are the electron configurations of an electrically neutral atom of sodium, electrically neutral atom of neon, and electrica
MA_775_DIABLO [31]
Na - 1s^2, 2s^2, 2p^6, 3s^1

Ne - 1s^2, 2s^2, 2p^6

O - 1s^2, 2s^2, 2p^4
4 0
3 years ago
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Evaluate (714 mm )/(37 s ) to three significant figures and express answer in si units using an appropriate prefix.
romanna [79]

The SI base units for length is meter (m) and for time is seconds (s).

The given ratio is \frac{714 mm}{37 s}

\frac{714 mm}{37 s} = 19.297 mm/s \simeq 19.3 mm/s

Converting mm/s to m/s as:

Since, 1 mm/s = 0.001 m/s

So, 19.3 mm/s = 0.0193 m/s

Since, zeroes to the left side of the non-zero number are not significant hence, the evaluation of \frac{714 mm}{37 s} to three significant figures and answer in SI units is 0.0193 m/s.

5 0
3 years ago
. How much energy is lost by a 30.0g sample of water that decreases in temperature from 56.7C to 25.0C?
lbvjy [14]

Answer:

Q = -3980.9 j

Explanation:

Given data:

Mass of sample = 30 g

Initial temperature = 56.7 °C

Final temperature = 25 °C

Specific heat of water = 4.186 j/g.°C

Amount of heat released = ?

Formula:

Q = m.c.ΔT

Q = heat released

m = mass of sample

c = specific heat of given sample

ΔT = change in temperature

Solution:

ΔT = T2 -T1

ΔT = 25 °C - 56.7 °C = - 31.7°C

Q = m.c.ΔT

Q = 30 g × 4.186 j/g.°C ×  - 31.7°C

Q = -3980.9 j

8 0
3 years ago
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