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2 years ago

15

A compact disc has a radius of 6 cm. If the disc rotates about its axis at a constant angular speed of 5 rev/s, what is the tota

l distance traveled by a point on the rim in 40 minutes

1 answer:

mojhsa [17]2 years ago

3 0

The total distance traveled is mathematically given as

d=4.5km

<h3>What is the total distance traveled?</h3>

Question Parameters:

A compact disc has a radius of 6 cm.

the constant angular speed of 5 rev/s

time 40 min

Generally, the equation for the linear speed is mathematically given as

v=w*r

Therefore

v=10 pi * 6

v=60pi cm/s

In conclusion, the equation of the distance

distance = v*t

d=60pi * 2400

d=452389.342 cm

d=4.5km

Read more about Distance

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3 years ago

Suppose you wish to fabricate a uniform wire out of 1.10 g of copper. If the wire is to have a resistance R = 0.390 Ω, and if al

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3 years ago

Glycerin (C3H8O3) is a nonvolatile liquid. What is the vapor pressure of a solution made by adding 154 g of glycerin to 316 mL o

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Answer:

$P_{sol}=50.4\ mm.Hg$

Explanation:

According to given:

molecular mass of glycerin, $M_g=3\times 12+8+3\times 16=92\ g.mol^{-1}$

molecular mass of water, $M_w=2+16=18\ g.mol^{-1}$

∵Density of water is $0.992\ g.cm^{-3}= 0.992\ g.mL^{-1}$

∴mass of water in 316 mL, $m_w=316\times 0.992=313.5 g$

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pressure of mixture, $P_x=55.32\ torr= 55.32\ mm.Hg$

temperature of mixture, $T_x=40^{\circ}C$

<em>Upon the formation of solution the vapour pressure will be reduced since we have one component of solution as non-volatile.</em>

<u>moles of water in the given quantity:</u>

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$n_w=\frac{313.5}{18}$

$n_w=17.42 moles$

<u>moles of glycerin in the given quantity:</u>

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$n_g=1.674 moles$

<u>Now the mole fraction of water:</u>

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$X_w=\frac{17.42}{17.42+1.674}$

$X_w=0.912$

<em>Since glycerin is non-volatile in nature so the vapor pressure of the resulting solution will be due to water only.</em>

$\therefore P_{sol}=X_w\times P_x$

$\therefore P_{sol}=0.912\times 55.32$

$P_{sol}=50.4\ mm.Hg$

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