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ehidna [41]
2 years ago
15

A compact disc has a radius of 6 cm. If the disc rotates about its axis at a constant angular speed of 5 rev/s, what is the tota

l distance traveled by a point on the rim in 40 minutes
Physics
1 answer:
mojhsa [17]2 years ago
3 0

The total distance traveled  is mathematically given as

d=4.5km

<h3>What is the total distance traveled?</h3>

Question Parameters:

A compact disc has a radius of 6 cm.

the constant angular speed of 5 rev/s

time 40 min

Generally, the equation for the linear speed   is mathematically given as

v=w*r

Therefore

v=10 pi * 6

v=60pi cm/s

In conclusion, the equation of the distance

distance = v*t

d=60pi * 2400

d=452389.342 cm

d=4.5km

Read more about Distance

brainly.com/question/4931057

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Answer:

(a) check attachment

(b)5 m/s²

Explanation:

Given: radius = 2.00mm: density = 2500kg/m³: viscosity of glycerin = 1.5pa: decity of glycerin = 1250kg/m³: g = 10N/kg = 10m/s²: Fdrag = 6πnrv

(a) for answer check attachment.

(b) For the magnitude of the balls initial acceleration:

     Initial net force(f) = mg - upthrust

                                  = mg - (\frac{m}{p} )pg.g

     acceleration (a) = Acceleration(a)=\frac{f}{m}\\=g - (\frac{pg}{p})g\\=g(1-\frac{pg}{p} )\\=10(1-\frac{1250}{2500} )\\a=10(1-0.5)\\a=5 m/s²

c.) fromthe force diagram in the attachment; when the ball attains terminal velocity the net force will be zero(0)

                                mg=6πnrv + upthrust

d.) For the magnitude of terminal velocity:

                                             mg=6πnrv + (\frac{m}{p})pg.g\\\\(\frac{4}{3}πr^{3} p)g=6πnrv +\frac{4}{3}πr^3pg.g\\\\V = \frac{2}{9}.\frac{(2*10^{-3})^{2}*(2500-1250)*10}{1.5}\\\\=0.79cm/s

e.) when the ball reaches terminal velocity, the acceleration is zero (0)

8 0
3 years ago
Jaden’s mass is 50 kilograms. His weight on Earth is newtons, and his weight on Mars is newtons.
MAXImum [283]
186 netwons on Mars and 490 netwons on earth
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Is Florida an example of an isthmus or a peninsula? Both Peninsula Neither Isthmus
aleksandrvk [35]

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Explanation:

Just did the Ed puzzle and got it right

3 0
3 years ago
Two balls of mass 0.09 kg hang on strings attached to the same point on the ceiling. The balls are given charges Q that cause th
telo118 [61]

Answer:

Q = 6.33μC

Explanation:

To find the value of the charge Q you take into account both gravitational force and electric force over each ball. By symmetry you can use the fact that both balls experiences the same forces. Hence you only take into account the forces for one ball for the x component and y component:

-Mg+Tcos\theta=0\\\\F_e-Tsin\theta=0

M: mass of the ball = 0.09kg

T: tension of the string

F_e: electric force between charges

angle = 45°

The electric force is given by:

F_e=k\frac{Q^2}{r^2}

Q: charge of the balls

r: distance between balls = 2m

You divide both equation in order to eliminate the tension T:

tan\theta=\frac{F_e}{Mg}=k\frac{Q^2}{Mgr^2}

By doing Q the subject of the formula and replacing you obtain:

Q=\sqrt{\frac{tan\theta Mgr^2}{k}}=\sqrt{\frac{tan45\°(0.09kg)(2m)^2}{(8.89*10^{9}Nm^2/C^2)}}=6.33*10^{-6}C=6.33\mu C

hence, the charge of the balls is 6.33μC

4 0
3 years ago
What is the acceleration of a 24 kg mass pushed by a 6N force?
olga nikolaevna [1]
0.25 m/s squared

hope this helps x
7 0
3 years ago
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