Answer:
Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu
Explanation:
- Copper (I) nitrate = CuNO₃ (Nitrate, NO₃⁻, always has a charge of -1).
- Iron (III) nitrate = Fe(NO₃)₃ (That way the compound has an overall neutral charge)
Writing the equation using symbols leaves us with:
- Fe + CuNO₃ → Fe(NO₃)₃ + Cu
<em>It is not balanced yet</em>. Now we <u>balance the NO₃ species on the left side</u>:
- Fe + 3CuNO₃ → Fe(NO₃)₃ + Cu
Finally we<u> balance the Cu species on the right side</u>:
- Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu
Susan should follow PEMDAS,
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction,
So, the first step should be, to solve the equation in the parentheses.
I hope this helps!
Answer:
Mass of sample in mg = 15,285 mg
Explanation:
Given:
Volume of urine sample = 15 ml
Density of sample = 1.019 g/ml
FInd:
Mass of sample in mg
Computation:
Mass = density x volume
Mass of sample in mg = Volume of urine sample x Density of sample
Mass of sample in mg = 1.019 x 15
Mass of sample in mg = 15.285 gram
Mass of sample in mg = 15.285 x 1,000
Mass of sample in mg = 15,285 mg
Approximately 119.4 g, you take the mass on the periodic table of each element and add the numbers up
