Answer:
Explanation:
Given that:
Pressure P = 10 atm
number of moles of N
= 1 mole
correction for the attractive force between molecule a = 1.352
correction for the volume of molecules b = 0.0387 L mol-1
Rate = 8.314
critical Temperature Tc= 126.3 K
Using van deer Waal equation:
So for 1 mole of N gas; we have
Recall that: Tc = 
and
Vc = 3b
Thus;
Vc= 3×(0.0387)
Vc = 0.1161m³
using the above Van der Waal equation, the value of V can also be determined, but in several situations, we abandon the term of (V - nb) and sometimes abandon 
depending on the circumstances.
Answer:
105mL of 0.7500M of NaOH are required
Explanation:
Phosphoric acid, H₃PO₄, reacts with sodium hydroxide, NaOH, as follows:
H₃PO₄ + 3 NaOH → Na₃PO₄ + 3H₂O
<em>Where 1 mole of phosphoric acid reacts with 3 moles of NaOH</em>
<em />
To solve this question we must find, as first, the moles of H3PO4 that react. Using the chemical equation we can find the moles of NaOH required to neutralize this acid. And, with its concentration, we can find the volume oof NaOH required:
<em>Moles H3PO4:</em>
35.00mL = 0.03500L * (0.7500mol / L) = 0.2625 moles H3PO4
<em>Moles NaOH:</em>
0.2625 moles H3PO4 * (3mol NaOH / 1mol H3PO4) = 0.07875 moles NaOH
<em>Volume NaOH:</em>
0.07875 moles NaOH * (1L / 0.7500mol) = 0.105L =
<h3>105mL of 0.7500M of NaOH are required</h3>
Answer:
See explanation and image attached
Explanation:
The Gilman reagent is a lithium and copper (diorganocopper) reagent with a general formula R2CuLi. R is an alkyl or aryl group.
They are useful in the synthesis of alkanes because they react with organic halides to replace the halide group with an R group.
In this particular instance, we intend to synthesize propylcyclohexane. The structure of the lithium diorganocopper (Gilman) reagent required is shown in the image attached to this answer.
