What did Scientist found that surprised them after making a map of the ocean floor?
1 answer:
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448 K is the final temperature of the water.
<h3>What is specific heat capacity?</h3>The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases by 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).
Given,
the mass of Na is 23 g
The volume of water = 293 cm3
Mass of water = 293 g
Total solution mass = 23 g + 293 g = 316 g
Specific heat capacity of water = 4.18 J/Kg
The equation relating mass, heat, specific heat capacity and temperature change is:
q = mcΔT
197 kJ = 316 g x 4.18 J/Kg x ()
197 kJ = 316 g x 4.18 J/Kg x ( -298 K)
0.1491429956 x 1000 = -298 K
149.1429956 + 298 =
447.1429956 =
448 K =
Hence, 448 K is the final temperature of the water.
<h3>What does a high specific heat capacity mean?</h3>A high specific heat capacity means that it can store a large amount of thermal energy for a small change in mass or temperature.
Learn more about specific heat capacity here:
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Answer:
1) 1.202 L
, 2) 1.291 dg
, 3) 204.877 and 4) 1.04x
Explanation:
You need to review about conversion factors and how to use them in the correct order. You can cancel the units and get the ones that you need if you use the appropriate conversion factors, remember is a number that you can use to multiply or divide.
For your exercise:
1) The conversion factor is: 1 L = 1000 mL
You will need to divide by 1000 mL to obtain liters L
1202.57120 mL x = 1.202 L
2) The conversion factor is: 1 g = 10 dg
0.1290743 g x = 1.291 dg
For the next exercises, you need to follow some rules:
1. All numbers that are different from Zero (non-zero digits) are significant figures.
2.The Zeros between non-zeros digits (Imbedded zeros) always are significant, 2007.
3. If you want to be specific and want some zeros to be significant you need to add a decimal point. For example 500. or 500.0
4. Leading zeros (to the left) are not significant.
5. Trailing zeros (zeros to the right) in a whole number without decimal point are not significant.
3) 843.062 - 638.1848 = 204.8772
Now if we round to 6 significant figures we get 204.877
4)123.0 x 8.43 = 1036.89
Now we round to 3 significant figures because 8.43 has the least significant figures.
1.04x