Question

5. What is the mass of 9.80 x 1023 formula units of zinc chlorate, Zn(CO3)2?

Answer 1

Answer:

$\boxed{\text{378 g}}$

Explanation:

We must convert formula units of Zn(ClO₃)₂ to moles and then to grams of Zn(ClO₃)₂.

Step 1. Convert formula units to moles

$\text{Moles of Zn(ClO _{3} ) _{2} }\\\\= 9.80 \times10^{23}\text{ formula units Zn(ClO _{3} ) _{2} } \times \dfrac{\text{1 mol Zn(ClO _{3} ) _{2} }}{6.022 \times\ 10^{23} \text{ formula units Zn(ClO _{3} ) _{2} }}\\\\= \text{1.627 mol Zn(ClO _{3} ) _{2} }$

Step 2. Convert moles to grams

$\text{Mass of Zn(ClO _{3} ) _{2} }\\\\= \text{1.627 mol Zn(ClO _{3} ) _{2} } \times \dfrac{\text{232.29 g Zn(ClO _{3} ) _{2} }}{\text{1 mol Zn(ClO _{3} ) _{2} }}\\\\= \text{378 g Zn(ClO _{3} ) _{2} }\\\\\text{The mass of Zn(ClO _{3} ) _{2} is } \boxed{\textbf{378 g}}$