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Oksanka [162]
3 years ago
8

When the temperature of a rigid hollow sphere containing 685 L of helium gas is held at 621 K, the pressure of the gas is 1.89 x

10^3 kPa. How many moles of the helium does the sphere contain? Please explain how you got the answer.
Chemistry
1 answer:
Leno4ka [110]3 years ago
8 0
You have to use the equation PV=nRT.
P=pressure (in this case 1.89x10^3 kPa which equals 18.35677 atm)
1V=volume (in this case 685L)
n=moles (in this case the unknown)
R=gas constant (0.08206 (L atm)/(mol K))
T=temperature (in this case 621 K)
with the given information you can rewrite the ideal gas law equation as n=PV/RT.
n=(18.35677atm x 685L)/(0.08206atmL/molK x 621K)
n=246.8 moles
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A 15.0-L scuba diving tank contains a helium-oxygen (heliox) mixture made up of 23.0 g of He and 4.14 g of O2 at 298 K. Calculat
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<u>Answer:</u> The mole fraction of Helium is 0.978 and that of oxygen gas is 0.022

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For helium:</u>

Given mass of helium = 23 g

Molar mass of helium = 4 g/mol

Putting values in equation 1, we get:

\text{Moles of helium}=\frac{23g}{4g/mol}=5.75mol

  • <u>For oxygen gas:</u>

Given mass of oxygen gas = 4.14 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of oxygen gas}=\frac{4.14g}{32g/mol}=0.129mol

Mole fraction of a substance is given by:

\chi_A=\frac{n_A}{n_A+n_B}

  • <u>For helium:</u>

Moles of helium = 5.75 moles

Total moles = [5.75 + 0.129] = 5.879 moles

Putting values in above equation, we get:

\chi_{(He)}=\frac{5.75}{5.879}=0.978

  • <u>For oxygen gas:</u>

Moles of oxygen gas = 0.129 moles

Total moles = [5.75 + 0.129] = 5.879 moles

Putting values in above equation, we get:

\chi_{(O_2)}=\frac{0.129}{5.879}=0.022

Hence, the mole fraction of Helium is 0.978 and that of oxygen gas is 0.022

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Explanation :

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Therefore, the time taken for the reaction is, 28 s.

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