Answer:
7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100 M solution.
Explanation:
First of all the molecular weight of Na2SO4 is 142.08 gram.Now we all know that if the molecular weight of a compound is dissolved in 1000ml or 1 litee of water then the strength of that solution becomes 1 M.
According to the given question we have to prepare 0.100 M solution
1000 ml of solution contain 142.08×0.1= 14.208 gram Na2SO4
1 ml of solution contain 14.208÷1000= 0.014 gram
0.5L or 500ml of solution contain 0.014×500= 7gram Na2SO4.
So it can be stated that 7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100M solution.
The density of the solid object will be 2.63 g/mL
<h3>What is density?</h3>
Density of objects = mass/volume.
Recall that an object will always displace its own volume when placed in a liquid.
Volume of the solid object = Cylinder reading after immersing the object in the water - cylinder reading before immersing the object in the water.
= 48.1 - 20.4
= 27.8 mL
Mass of the solid object = 73.05 g
Density of the object = 73.05/27.8
= 2.63 g/mL
More on density can be found here: brainly.com/question/15164682
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Answer: Too much base was added
i guessed
Explanation:
Answer:
Each gas have same number of molecules.
Explanation:
According to Avogadro law,
Equal volume of all the gases at same temperature and pressure have equal number of molecules.
Mathematical expression:
V ∝ n
V = Kn
V/n = K
k = constant
V = volume of gas
n = number of moles of gas
when volume change is changed from v1 to v2 and number of moles from n1 to n2 this law can be written as,
V1 / n1 = V2 /n2
This state that by increasing the number of moles of gas volume also goes to increase.
