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postnew [5]
3 years ago
11

Write an equation for the hydrogenation of glyceryl trilinolenate, a fat formed from glycerol and three linolenic acid molecules

.
Chemistry
1 answer:
Tomtit [17]3 years ago
5 0

Balanced chemical equation for the hydrogenation of glyceryl trilinolenate:

C₅₇H₉₂O₆ + 9H₂ → C₅₇H₁₁₀O₆.

Linolenic acid (octadecatrienoic acids ) is a type of fatty acid. It has 18 carbon atoms chain and three double bonds. So trilinolenate has nine double bonds.

Trilinolenate is the form of triglyceride esters of linolenic acid.

Hydrogenation is addition of hydrogen atoms at both sides of a double bond.

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write a balanced chemical equation for each single replacement reaction that takes place in aqueous solution. write no reaction
Illusion [34]

The question is incomplete, here is the complete question:

Write a balanced chemical equation for each single replacement reaction that takes place in aqueous solution. write no reaction if a reaction does not occur

1.) Zn + PbCl₂

2.) Cu + Fe(NO₃)₂

<u>Answer:</u>

<u>For 1:</u> The reaction does occur.

<u>For 2:</u> The reaction does not occur.

<u>Explanation:</u>

Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element.

The reactivity of metal is determined by a series known as reactivity series. The metals lying above in the series are more reactive than the metals which lie below in the series.

A+BC\rightarrow AC+B

For the given options:

  • <u>For 1:</u>

Zinc is more reactive than lead as it lies above in the series. So, it will displace lead from its chemical equation.

The chemical equation for the reaction of zinc and lead chloride follows:

Zn+PbCl_2\rightarrow ZnCl_2+Pb

  • <u>For 2:</u>

Copper is less reactive than iron as it lies below in the series. So, it will not displace iron from its chemical equation.

The chemical equation for the reaction of copper and iron (II) nitrate follows:

Cu+Fe(NO_3)_2\rightarrow \text{No reaction}

3 0
3 years ago
The organelle that is responsible for making glucose is the ____.
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3 years ago
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What mass of precipitate forms when 185.5 ml of 0.533 m naoh is added to 627 ml of a solution that contains 15.8 g of aluminum s
Law Incorporation [45]

Answer:

2,57 g of precipitate.

Explanation:

For the reaction:

6 NaOH + Al₂(SO₄)₃ → 2 Al(OH)₃ + 3 Na₂SO₄

The precipitate is Al(OH)₃.

185,5mL of 0,533M NaOH are:

0,1855L × 0,533M = <em>0,0989 moles NaOH</em>

Moles of Al₂(SO₄)₃ are:

15,8g × \frac{1mol}{342,15g} = <em>0,0462 moles Al₂(SO₄)₃</em>

For the total reaction of 0,0989 moles NaOH with Al₂(SO₄)₃ you need:

0,0989moles NaOH × \frac{1molAl_{2}(SO_{4})_{3}}{6 moles NaOH} = <em>0,0165 moles Al₂(SO₄)₃</em>

As you have <em>0,0462 moles Al₂(SO₄)₃ </em>the limiting reactant is NaOH.

0,0989 moles of NaOH produce:

0,0989moles NaOH × \frac{2molAl(OH)_{3}}{6 moles NaOH} = <em>0,0330 moles of Al(OH)₃</em>

These moles are:

0,0330 moles of Al(OH)₃ × (78 g/mol) = <em>2,57 g of Al(OH)₃ ≡ mass of precipitate</em>

<em></em>

I hope it helps!

<em> </em>

3 0
3 years ago
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