Write an equation for the hydrogenation of glyceryl trilinolenate, a fat formed from glycerol and three linolenic acid molecules
1 answer:
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Answer:
The final temperature of the system is 27.3°C.
Explanation:
Heat lost by aluminum = 3.99 × 0.91 × (100-T)
= 3.631 (100-T)
Heat gained by water = 10 × 4.184 × (T-21)
= 41.84 (T-21)
As,
Heat gained = Heat loss
or, 3.631(100-T) = 41.84(T-21)
or,363.1 - 3.631 T = 41.84 T - 878.64)
or, (41.84+ 3.631) T = 878.64 +363.1
or T=
or, T = 27.3°C
Hence the final temperature is 27.3°C.
<u>Answer:</u> The percent gallium in gallium bromide is 30.30 %.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of gallium bromide = 0.165 g
Molar mass of titanium gallium bromide = 229.53 g/mol
Putting values in equation 1, we get:
- The chemical equation for the reaction of gallium bromide and silver nitrate follows:
By Stoichiometry of the reaction:
1 moles of gallium bromide produces 1 mole of gallium nitrate
So, 0.00072 moles of gallium bromide will produce = of gallium nitrate
- Now, calculating the mass of gallium nitrate from equation 1, we get:
Molar mass of gallium nitrate = 193.73 g/mol
Moles of gallium nitrate = 0.00072 moles
Putting values in equation 1, we get:
Calculating the mass of gallium in the reaction, we use unitary method:
In 1 mole of gallium nitrate, 1 mole of gallium atom is present.
In 193.73 grams of gallium nitrate, 69.72 g of gallium atom is present.
So, in 0.139 grams of gallium nitrate, the mass of gallium present will be =
- To calculate the percentage composition of gallium in gallium bromide, we use the equation:
Mass of gallium bromide = 0.165 g
Mass of gallium = 0.050 g
Putting values in above equation, we get:
Hence, the percent gallium in gallium bromide is 30.30 %.