The work done by the normal force n when the box slides down a frictionless incline and gaining speed is zero.
<h3>What is normal force?</h3>
The force of contact is called the normal force. When the two surfaces are in contact with each other, then the normal force acts.
This force is applied by the solid bodies on each other in order to prevent the passing through each other.
A box slides down a frictionless incline, gaining speed. For this box, the value of work done by normal force has to be found out. Let's analyze the given condition.
- The body is gaining the speed, which means there is a change in kinetic energy.
- The change in kinetic energy is equal to the work done.
- The friction force is the product of coefficient of the friction and normal force.
- The friction force for the given case is zero. Thus, the normal force must be equal to the zero.
Thus, the work done by the normal force n when the box slides down a frictionless incline and gaining speed is zero.
Learn more about the normal force here;
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Work done = force * distance
work done = 200 * 20
work done = 4000J
Answer: A.The ocean is colder than the land
Explanation:
Based on the information provided in the question, we are informed that Agustin visits Panama City, Florida, during the month of May and that he feels a shore breeze blowing from the ocean onto the beach.
The reason for the shore breeze is simply due to the fact that the ocean is colder than the land. Since the ocean is colder, anyone who goes to the beach will feel the breeze.
516.154 megawatts of heat are <em>exhausted</em> to the river that cools the plant.
By definition of energy efficiency, we derive an expression for the energy rate exhausted to the river (
), in megawatts:
(1)
Where:
- Efficiency.
- Electric power, in megawatts.
If we know that 
and 
, then the energy rate exhausted to the river is:
516.154 megawatts of heat are <em>exhausted</em> to the river that cools the plant.
We kindly to check this question on first law of thermodynamics: brainly.com/question/3808473
Answer:
K = 0.076 J
Explanation:
The height of the target, h = 0.860 m
The mass of the steel ball, m = 0.0120 kg
Distance moved, d = 1.50 m
We need to find the kinetic energy (in joules) of the target ball just after it is struck. Let t is the time taken by the ball to reach the ground.
Put all the values,
The velocity of the ball is :
The kinetic energy of the ball is :
So, the required kinetic energy is 0.076 J.
