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3 years ago

11

In 1900, a German physicist discovered an equation that matched experimental data about the emission of light by a hot surface.

*
a. Max Planck
b. Sir Isaac Newton
c. James Clerk Maxwell
d. Christian Huygens

2 answers:

GREYUIT [131]3 years ago

8 0

C is the correct answer.
James Clerk Maxwell

USPshnik [31]3 years ago

5 0

C. James Clerk Maxwell
I believe he made a theory that light was electromagnetic radiation

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A gas sample is heated from -20.0°C to 57.0°C and the volume is increased from 2.00 L to 4.50 L. If the initial pressure is 0.14

Svetach [21]

Answer:

The answer is e.

Explanation:

We take:

$T_{1}=253K$

$V_{1}=2.00 l$

$P_{1}=0.14atm$

$V_{2}=4.50 l$

$T_{2}=330K$

Taking the gas as an ideal gas, we can use the ideal gas law:

$\frac{PV}{nRT}$

⇒ $n=\frac{P_{1}V_{1}}{RT_{1}}$ ⇒ $n=0.013mol$

Then:

$P_{2}=\frac{nRT_{2}}{V_{2}}$ ⇒ $P_{2}=0.0811 atm$

Taking R=0.08205atmL/molK.

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3 years ago

Calculate the momentum pelephant of a 2140 kg elephant charging a hunter at a speed of 7.63 m/s . pelephant= kg⋅m/s Compare the

Zepler [3.9K]

Answer:

Momentum of elephant is greater than momentum of tranquilizer dart

Explanation:

$m_e$ = Mass of elephant = 2140 kg

$m_d$ = Mass of tranquilizer dart = 0.0415 kg

$v_e$ = Velocity of elephant = 7.63 m/s

$v_e$ = Velocity of tranquilizer dart = 619 m/s

Momentum of elephant

$p_e=m_ev_e\\\Rightarrow p_e=2140\times 7.63\\\Rightarrow p_e=16328.2\ N.s$

Momentum of tranquilizer dart

$p_d=m_dv_d\\\Rightarrow p_d=0.0415\times 619\\\Rightarrow p_d=25.6885\ N.s$

So, $p_e>p_d$

Momentum of elephant is greater than momentum of tranquilizer dart

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Describe what happens to the gravitational force when the Sun, Earth and Moon<br> are in a line.

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Answer:

a spring tide occurs

Explanation:

ithe gravitational pull makes that tide happen

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3 years ago

In a discussion person A is talking 1.2 dB louder than person B, and person C is talking 3.2 dB louder than person A. What is th

liberstina [14]

Answer: 3.84dB

Explanation:

Since person A is talking 1.2dB louder than B, we will have

A = 1.2B... (1)

Similarly, person C is talking 3.2 dB louder than person A, we have

C = 3.2A... (2)

From equation 1, B = A/1.2... (3)

To get the ratio of the sound intensity of person C to the sound intensity of person B, we will divide equation 2 by 3 to give

C/B = 3.2A/{A/1.2}

C/B = 3.2A×1.2/A

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pickupchik [31]

Answer:

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lowest part on the graph (closest to x-axis)

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