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Bogdan [553]
3 years ago
15

Which is colder dry ice or dioxide gas

Chemistry
2 answers:
Eddi Din [679]3 years ago
8 0
Dry ice is the solid form of dioxide gas , and I think dry ice is colder because its frozen
Juli2301 [7.4K]3 years ago
6 0
Dioxide gas because ita cooler
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When an acidic molecule is added to water it will ____________ the pH of the solution because it increases the number of free __
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Lower the pH because increased number of free hydrogen ions
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Nitric oxide (NO) reacts readily with chlorine gas as follows.2 NO(g) + Cl2(g) equilibrium reaction arrow 2 NOCl(g)At 700. K the
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<u>Answer:</u>

<u>For a:</u> The mixture will need to produce more reactants to reach equilibrium.

<u>For b:</u> The mixture will need to produce more reactants to reach equilibrium.

<u>For c:</u> The mixture will need to produce more products to reach equilibrium.

<u>Explanation</u>:

For the given chemical equation:

2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)

The expression of K_{p} for above equation follows:

K_{p}=\frac{(p_{NOCl})^2}{(p_{NO})^2\times p_{Cl_2}}   .....(1)

We are given:

Value of K_p = 0.26

There are 3 conditions:

  • When K_{p}>Q_p; the reaction is product favored.
  • When K_{p}; the reaction is reactant favored.
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For the given options:

  • <u>For a:</u>

We are given:

p_{NOCl}=0.11atm\\p_{NO}=0.16atm\\p_{Cl_2}=0.30atm

Putting values in expression 1, we get:

Q_p=\frac{(0.11)^2}{(0.16)^2\times 0.30}=1.57

As, K_{p}; the reaction is reactant favored

Hence, the mixture will need to produce more reactants to reach equilibrium.

  • <u>For b:</u>

We are given:

p_{NOCl}=0.048atm\\p_{NO}=0.12atm\\p_{Cl_2}=0.10atm

Putting values in expression 1, we get:

Q_p=\frac{(0.048)^2}{(0.12)^2\times 0.10}=1.6

As, K_{p}; the reaction is reactant favored

Hence, the mixture will need to produce more reactants to reach equilibrium.

  • <u>For c:</u>

We are given:

p_{NOCl}=5.20\times 10^{-3}atm\\p_{NO}=0.15atm\\p_{Cl_2}=0.15atm

Putting values in expression 1, we get:

Q_p=\frac{(5.20\times 10^{-3})^2}{(0.15)^2\times 0.15}=0.008

As, K_{p}>Q_p; the reaction is product favored.

Hence, the mixture will need to produce more products to reach equilibrium.

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