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2 years ago

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Chemistry

1 answer:

Softa [21]2 years ago

6 0

If the colored spheres are solutes, the overall direction of water would be out of the cell based on the principle of osmosis.

<h3>What is osmosis</h3>

It is the movement of water molecules from the region of high water potential (low solutes) to the region of low water potential (high solute) through a selectively permeable membrane.

In the illustration, there are more colored spheres outside of the cell than inside of it. This means that there are more solutes outside the cell (lower water potential) than inside of the cell (higher water potential).

Thus, water will move from the inside of the cell to the outside until an equilibrium is established.

More on osmosis can be found here: brainly.com/question/1799974

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How many moles are there in 1.505 X 1024 molecules of water, H2O?

KATRIN_1 [288]

Answer:

2.5 moles

Explanation:

Nᴀ=6.02×10²³ (constant)

n=N/Nᴀ=

$= \frac{1.505 \times 10 ^{24} }{ {6.02 \times 10}^{23} } = 2.5 \: moles$

5 0

3 years ago

You wish to measure the iron content of the well water on the new property you are about to buy. You prepare a reference standar

djverab [1.8K]

1.04 ⨯ 10 $^{-4}$ M

<h3>Explanation</h3>

<em>A</em> = <em>ε</em> $\cdot l \cdot c$ by the Beer-Lambert law, where

<em>A</em> the absorbance,
$l$ the path length,
<em>ε</em> the molar absorptivity of the solute, and
$c$ concentration of the solution.

<em>A</em> and <em>ε </em>are the same for both solutions. Therefore, $l \cdot c$ is constant; $l$ is inversely proportional to $c$ . The 100 mL sample would have a concentration 1/4.78 times that of the 45.0 mL reference.

The 13.0 mL standard solution has a concentration of 5.17 ⨯ $10^{-4}$ M. Diluting it to 45.0 mL results in a concentration of $5.17 \times 10^{-4} \times \frac{13.0}{45.0} =$ 1.494 M.

$c$ is inversely related to $l$ for the two solutions. As a result, c₂ = $c_1 \cdot \frac{l_1}{l_2} = 1.494 \times 10^{-4} \times \frac{1}{4.78} =$ 3.126 M.

The 30.0 mL sample has to be diluted by 30.0 / 100.0 times to produce the 100.0 mL solution being tested. The 100.0 mL solution has a concentration of 3.126 M. Therefore, the 30.0 mL solution has a concentration of $3.126 \times \frac{100.0}{30.0} =$ 1.04 ⨯ $10^{-4}$ M.

6 0

3 years ago

Ca(OH)2 + H2SO4 ⟶2H2O + CaSO4 What volume of 1.45 M Ca(OH)2 is needed to react with 25.0 moles of H2SO4?

Shkiper50 [21]

Answer:

We need 17.2 L of Ca(OH)2

Explanation:

Step 1: Data given

Concentration of Ca(OH)2 = 1.45 M

Moles of H2SO4 = 25.0 moles

Step 2: The balanced equation

Ca(OH)2 + H2SO4 ⟶2H2O + CaSO4

Step 3: Calculate moles Ca(OH)2

For 1 mol Ca(OH)2 we need 1 mol H2SO4 to produce 2 moles H2O and 1 mol CaSO4

For 25.0 moles H2SO4 we'll need 25.0 moles Ca(OH)2 to produce 50 moles H2O and 25.0 moles CaSO4

Step 4: Calculate volume of Ca(OH)2

Volume Ca(OH)2 = moles Ca(OH)2 / concentration Ca(OH)2

Volume Ca(OH)2 = 25.0 moles / 1.45 M

Volume Ca(OH)2 = 17.2 L

We need 17.2 L of Ca(OH)2

3 0

3 years ago

What volume will 2.04g of helium gas occupy at 100C and 1.13 atm?

Igoryamba

Answer:

1.13 atm

Explanation:

6 0

3 years ago

The force of 20 N acts upon a 5kg block. What is the acceleration of the block?

charle [14.2K]

Answer:

<h2>The answer is 4 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

$a = \frac{f}{m} \\$

where

a is the acceleration

f is the force

m is the mass

From the question

f = 20 N

m = 5 kg

We have

$a = \frac{20}{5} \\$

We have the final answer as

Hope this helps you

8 0

3 years ago