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3 years ago

In our simulation what did the σ (sigma) stand for?

Chemistry

1 answer:

jenyasd209 [6]3 years ago

3 0

Answer:

The atomic radius corresponds to Sigma

Explanation:

It is the Van Der Waals radius ;)

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One sentence describing the difference between pure substances and mixtures.

Alja [10]

Answer:

A pure substance is made up of only one ingredient or combination. A mixture is made up of two or maybe more separate components that are not chemically linked.

Explanation:

6 0

3 years ago

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What ion carries two negative charges and is isoelectronic with k+?

lutik1710 [3]

The answer is: " S²⁻ " .
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3 years ago

Based on its type of chemical bond, which substance has the highest boiling point?

Ber [7]

Answer: Lithium Fluoride

Explanation: Let’s see,,,
1. Obviously not hydrogen or carbon dioxide because they’re gas at room temp.
2. Lithium Fluoride is an ionic compound which means they have higher intermolecular forces and require more energy to break them, so it probably has a higher boiling point.

7 0

3 years ago

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Determine the molarity of a solution prepared by dissolving 141.6 g of citric acid , c3h5o(cooh)3 , in water and then diluting t

gogolik [260]

The molarity of a solution prepared by dissolving 141.6g of citric acid in water is calculated as below

find the the number of moles

moles= mass/molar mass

= 141.6 g/ 192 g/mol = 0.738 moles

molarity= moles/molar mass

= 0.738/3500 x1000 = 0.21 M

3 0

4 years ago

Lithium has two stable isotopes with masses of 6.01512 amu and 7.01600 amu. The average molar mass of Li is 6.941 amu. What is t

Dvinal [7]

Answer : The percent abundance of Li isotope-1 and Li isotope-2 is, 6.94 % and 93.1 % respectively.

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of Li isotope-1 be 'x' and the fractional abundance of Li isotope-2 will be '100-x'

For Li isotope-1 :

Mass of Li isotope-1 = 6.01512 amu

Fractional abundance of Li isotope-1 = x

For Li isotope-2 :

Mass of Li isotope-2 = 7.01600 amu

Fractional abundance of Li isotope-2 = 100-x

Average atomic mass of Li = 6.941 amu

Putting values in equation 1, we get:

$6.941=[(6.01512\times x)+(7.01600\times (100-x))]$

By solving the term 'x', we get:

$x=694.048$

Percent abundance of Li isotope-1 = $\frac{694.048}{100}=6.94\%$

Percent abundance of Li isotope-2 = 100 - x = 100-6.94 = 93.1 %

6 0

3 years ago