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dezoksy [38]
3 years ago
15

What is the standard state of oxygen?

Chemistry
2 answers:
Darina [25.2K]3 years ago
8 0
To oxygen atoms combined to form <span>O_2[/tex] so they share electrons. They are in gas forms</span>
Simora [160]3 years ago
4 0
O2 gas, where there are two Oxygen atoms which are covalently bonded together
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A solution contains 0.10 m sodium cyanide and 0.10 m potassium hydroxide. solid zinc acetate is added slowly to this mixture. wh
Brrunno [24]
1) Zn(CH₃COO)₂(s) + 2KOH(aq) = Zn(OH)₂(s) + 2CH₃COOK(aq)

Ksp{Zn(OH)₂}=1.2*10⁻¹⁷

2) Zn(CH₃COO)₂(s) + 2NaCN(aq) = Zn(CN)₂(s) + 2CH₃COONa(aq)

Ksp{Zn(CN)₂}=2.6*10⁻¹³


Ksp{Zn(OH)₂}<Ksp{Zn(CN)₂}

Zn(OH)₂ precipitates first

6 0
3 years ago
What is the total number of atoms in molecule hno3?
forsale [732]
5. 1 hydrogen, 1 Nitrogen, 3 oxygen
8 0
3 years ago
When you light a match, there is a brief Smell that almost burns your nose
Diano4ka-milaya [45]

Answer:

Hdhgfrdf

Explanation:

8 0
4 years ago
Read 2 more answers
True or false? Enzymes in the digestive tract catalyze hydrolysis reactions.
Slav-nsk [51]

Answer:

The given statement is true.

Enzymes which are present in the digestive tract such as salivary amylase, pepsin, trypsin, et cetera mainly catalyze the hydrolysis reaction.

The hydrolysis reaction is the reaction by which large molecules are broken down into smaller molecules with the help of water.

Most of the complex molecules or nutrients such as starch, protein et cetera are broken down into their respective smaller units with the help of hydrolysis reaction.

For example, lactase catalyzes the hydrolysis of lactose into glucose and galactose.

5 0
3 years ago
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The buffer solution is used to control the pH to insure that it does not become too high because excessively basic solutions cou
oksian1 [2.3K]

Answer:

pH = 12.7

Explanation:

First, we have to calculate the [Ca²⁺] in a solution of about 250 ppm CaCO₃.

\frac{250mgCaCO_{3}}{L} .\frac{1gCaCO_{3}}{1000mgCaCO_{3}} .\frac{1molCa^{2+} }{100gCaCO_{3}} =2.5 \times 10^{-3} M

Now, let's consider the dissolution of Ca(OH)₂ in water.

Ca(OH)₂(s) ⇄ Ca²⁺(aq) + 2 OH⁻(aq)

The solubility product Ksp is:

Ksp = [Ca²⁺] × [OH⁻]²

[OH⁻] = √(Ksp/[Ca²⁺]) = √(6.5 × 10⁻⁶/2.5 × 10⁻³) = 5.1 × 10⁻² M

Finally, we can calculate pOH and pH.

pOH = -log [OH⁻] = -log (5.1 × 10⁻²) = 1.3

pH + pOH = 14 ⇒ pH = 14 - pOH = 14 - 1.3 = 12.7

5 0
3 years ago
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