Missing question: A possible atomic weight of Q is?
A)12.7.
B)19.0.
C)27.5
D)38.0
E)57.0.
Answer is: possible atomic weight of Q is B) 19.0.
Molecular weight of first molecule is 38.0 g/mol.
Molecular weight of second molecule is 57.0 g/mol.
Molecular weight of third molecule is 76.0 g/mol.
Molecular weight of fourth molecule is 114.0 g/mol.
All four molecular weights can be division only by 19 to get whole number:
Molecule 1 (38 ÷ 19 = 2), molecule 2 (57 ÷ 19 = 3), molecule 3 (76 ÷ 19 = 4) and molecule 4 ( 114 ÷ 19 = 6).
Molecular formulas are than Q₂, Q₃, Q₄ and Q₆.
Answer:
Most likely Potential Energy
Explanation:
This is possible because potential energy is stored energy that an object contains until moved, once moved it transfers its potential energy into kinetic energy. In this problem, the kinetic energy in the torch is changed into potential energy once placed on the shelf and deprived of movement. Thus your only viable answer is Potential energy!
Hope this helps, please comment in case wrong so I may figure it out and correct my mistakes
Answer:
0.001 mole of NaF.
Explanation:
From the question given above, the following data were obtained:
Volume of solution = 100 mL
Molarity = 0.01 M
Mole of NaF =?
Next, we shall convert 100 mL to litre (L). This can be obtained as follow:
1000 mL = 1 L
Therefore,
100 mL = 100 mL × 1 L / 1000 ml
100 mL = 0.1 L
Thus, 100 mL is equivalent to 0.1 L.
Finally, we shall determine the number of mole of NaF present in the solution. This can be obtained as follow:
Volume of solution = 0.1 L
Molarity = 0.01 M
Mole of NaF =?
Molarity =mole /Volume
0.01 = mole of NaF / 0.1
Cross multiply
Mole of NaF = 0.01 × 0.1
Mole of NaF = 0.001 mole.
Thus, 0.001 mole of NaF is present in 100 mL of the solution.
Answer:
The main energy levels are the shells where the electron resides in a location that's relative to the atom's nucleus.
Explanation:
In electronic configuration in chemistry, the main energy levels are the shells where the electron resides in a location that's relative to the atom's nucleus. Such an energy level is usually denoted by the principal quantum number n. So n can be 1,2,3,4...e.t.c
Answer:
A. is most likely the answer
