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3 years ago

An ion in a mass spectrometer follows a semicircular path of radius 14.8. What is the distance it travels?

2 answers:

7 0

The circumference of a circle is (2π · the circle's radius).

The length of a semi-circle is (1π · the circle's radius) =

(π · 14.8) = 46.5 (rounded)

(The unit is the same as whatever the unit of the 14.8 is.)

Y_Kistochka [10]3 years ago

4 0

Is there a time frame in which it travels?

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Describing the Changes in the Ator Based on the article "Will the real atomic model please stand up?,"describe one major change

andrew11 [14]

Answer: the last period. i think has the largest energy level

Explanation:

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3 years ago

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Electron spin: Radio astronomers can detect clouds of hydrogen too cool to radiate optical wavelengths of light by means of the

Ivan

Answer:

the magnetic field experienced by the electron is 0.0511 T

Explanation:

Given the data in the question;

Wavelength λ = 21 cm = 0.21 m

we know that Bohr magneton μ $_B$ is 9.27 × 10⁻²⁴ J/T

Plank's constant h is 6.626 × 10⁻³⁴ J.s

speed of light c = 3 × 10⁸ m/s

protein spin causes magnetic field in hydrogen atom.

Initial potential energy = -μ $_B$ B × cos0°

= -μ $_B$ B × 1

= -μ $_B$ B

Final potential energy = -μ $_B$ B × cos180°

= -μ $_B$ B × -1

= μ $_B$ B

so change in energy will be;

ΔE = μ $_B$ B - ( -μ $_B$ B )

ΔE = 2μ $_B$ B

now, difference in energy levels will be;

ΔE = hc/λ

2μ $_B$ B = hc/λ

2μ $_B$ Bλ = hc

B = hc / 2μ $_B$ λ

so we substitute

B = [(6.626 × 10⁻³⁴) × (3 × 10⁸)] / [2(9.27 × 10⁻²⁴) × 0.21 ]

B = [ 1.9878 × 10⁻²⁵ ] / [ 3.8934 × 10⁻²⁴ ]

B = 510556326.09

B = 0.0511 T

Therefore, the magnetic field experienced by the electron is 0.0511 T

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3 years ago

If a question asks about velocity in a projectile, is it referring to the vertical or horizontal velocity? An example where this

deff fn [24]

Explanation:

If it doesn't specify vertical or horizontal, that means it wants you to find the total velocity. You can do that using Pythagorean theorem:

v² = vₓ² + vᵧ²

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4 years ago

Two loudspeakers are placed 1.8 m apart. They play tones of equal frequency. If you stand 3.0 m in front of the speakers, and ex

Ahat [919]

The question is incomplete. The complete question is :

Two loudspeakers are placed 1.8 m apart. They play tones of equal frequency. If you stand 3.0 m in front of the speakers, and exactly between them, you hear a minimum of intensity. As you walk parallel to the plane of the speakers, staying 3.0 m away, the sound intensity increases until reaching a maximum when you are directly in front of one of the speakers. The speed of sound in the room is 340 m/s.

What is the frequency of the sound?

Solution :

Given :

The distance between the two loud speakers, $d = 1.8 \ m$