The Earth’s average orbital speed expressed in kilometers per hours is 107225.5 Km/hr and the mass of the sun is 2.58 x
Kg
<h3>
Relationship between Linear and angular speed</h3>
Linear speed is the product of angular speed and the maximum displacement of the particle. That is,
V = Wr
Where
Given that the earth orbits the sun at an average circular radius of about 149.60 million kilometers every 365.26 Earth days.
a) To determine the Earth’s average orbital speed, we will make use of the below formula to calculate angular speed
W = 2
/T
W = (2 x 3.143) / (365.26 x 24)
W = 6.283 / 876624
W = 7.2 x
Rad/hr
The Earth’s average orbital speed V = Wr
V = 7.2 x
x 149.6 x 
V = 107225.5 kilometers per hours.
b) Based on the information given in this question, to calculate the approximate mass of the Sun, we will use Kepler's 3rd law
M = (4
) / G
M = (4 x 9.8696 x 3.35 x
) / (6.67 x
x 7.68 x
<em>)</em>
<em>M = 1.32 x </em>
/ 51.226
M = 2.58 x
Kg
Therefore, the Earth’s average orbital speed expressed in kilometers per hours is 107225.5 Km/hr and the mass of the sun is 2.58 x
Kg
Learn more about Orbital Speed here: brainly.com/question/22247460
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Answer:
Explanation:
i dont speak arbic so ill take the points
<h2>
Horizontal component of the rock’s velocity when it strikes the ground is 17.25 m/s</h2>
Explanation:
In horizontal direction there is no acceleration or deceleration for a rock projected at an initial angle of 37° off the ground.
So the horizontal component of velocity always remains the same.
Horizontal component of velocity is the cosine component of velocity.
Initial velocity, u = 21.6 m/s
Angle, θ = 37°
Horizontal component of velocity = u cosθ
Horizontal component of velocity = 21.6 cos37
Horizontal component of velocity = 17.25 m/s
Since the horizontal velocity is unaffected, we have
Horizontal component of the rock’s velocity when it strikes the ground = 17.25 m/s
Answer:
gravity keeps the planets in orbit around the sun