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2 years ago

To span the distance between two switches, why is adding an intermediate switch not an attractive choice

1 answer:

3 0

Adding an intermediate switch is not an attractive choice to span the distance between two switches due to expense issues. It may have different ports.

<h3>What is a network switch?</h3>

A switch refers to a hardware tool capable of connecting different computer devices in a network.

A network switch can connect devices on a network by centralizing communications among many devices in a given local area network.

A switch may support different speeds for transmission of data (for example, one gigabit Gbps per second).

Learn more about network switches here:

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Groundwater returning to earths surface comes up through a ___?

Harrizon [31]

Answer:

Groundwater Returning to earths Surface come Up Though A drought

Explanation:

THIS DOES NOT NEED TO BE EXPLAINED IT'S EZZZ

8 0

2 years ago

A particle undergoes two displacements. The first has a magnitude of 11 m and makes an angle of 82 ◦ with the positive x axis. T

Luden [163]

Answer:

$\theta = 211.7 degree$

Explanation:

First displacement of the particle is given as

$r_1$ = 11 m at 82 degree with positive X axis

so we can say

$\vec r_1 = 11 cos82 \hat i + 11 sin82 \hat j$

$\vec r_1 = 1.53\hat i + 10.9 \hat j$

resultant displacement of the particle after second displacement is given as

r = 8.7 m at 135 degree with positive X axis

so we can say

$r = 8.7 cos135\hat i + 8.7 sin135\hat j$

$r = -6.15 \hat i + 6.15 \hat j$

now we know that

$r = r_1 + r_2$

now we have

$r_2 = r - r_1$

so we will have

$r_2 = (-6.15 \hat i + 6.15 \hat j) - (1.53\hat i + 10.9 \hat j)$

$r_2 = -7.68 \hat i - 4.75 \hat j$

so angle of the second displacement is given as

$tan\theta = \frac{r_y}{r_x}$

$tan\theta = \frac{-4.75}{-7.68}$

$\theta = 211.7 degree$

8 0

3 years ago

Suppose that a public address system emits sound uniformly in all directions and that there are no reflections. The intensity at

dybincka [34]

Answer:

The intensity at a spot 71 m away is $4.02*10^{-5} Wm^{-2}$

Explanation:

Given:

Initial intensity, $I_{1}=3.0*10^{-4} Wm^{-2}$ at a distance, $d_{1} = 26 m$

Required:

New intensity, $I_{2} =?$ at a distance, $d_{2} = 71 m$

Using the inverse square law,

I ∝ $\frac{1}{d^{2} }$

⇒ $I_{1}$ $I_{1}d_{1}^{2} =I_{2}d_{2}^{2}$

$I_{2} =\frac{I_{1} d_{1}^{2} }{d_{2}^{2}} =\frac{3.0*10^{-4}*26^{2} }{71^{2} } \\$ ×

$I_{2}=4.02*10^{-5} Wm^{-2}$

Thus, the intensity at a spot that is 71 m away is $4.02*10^{-5} Wm^{-2}$

5 0

3 years ago

A proton and an electron are both accelerated to the same final speed. If λp s the de Broglie wavelength of the proton and e is

meriva

Answer:

Explanation:

The relation between the de Broglie wavelength and the momentum of the particle is given by

$\lambda =\frac{h}{m\times v}$

where, m is the mas of the particle and v be the velocity of the particle and h be the Plank's constant.

So, the de broglie wavelength of proton is given by

$\lambda _{p}=\frac{h}{m_{p}\times v}$ .... (1)

The de broglie wavelength of electron is given by

$\lambda _{e}=\frac{h}{m_{e}\times v}$ .... (2)

Divide equation (2) by equation (1), we get

$\frac{\lambda _{e}}{\lambda _{p}}=\frac{m_{p}}{m_{e}}$

As the mass of proton is much more than the mass of electron, so the de broglie wavelength of electron is more than the de Broglie wavelength of proton.

5 0

3 years ago

Shown here are astronomical objects located at different distances from Earth. Rank the objects based on their distances from Ea

nevsk [136]

Answer: star on far side of Andromeda Galaxy- star on near side of Andromeda Galaxy- star on far side of Milky Way Galaxy- star near center of Milky Way Galaxy- Orion Nebula- Alpha Centauri- Pluto-The Sun

Explanation:

Andromeda is the nearest spiral galaxy to our Milky way galaxy. The star on the far side of the Andromeda galaxy would be farthest from Earth. Then, the star at the near side of the Andromeda galaxy.

The Earth along with the Sun and other planets are located in the Orion arm of the Milky way. It is about 8 kpc from the center of the Milky way. Thus, the next farthest astronomical object would be the star on the far side of the milky way and then a star near the center of the Milky way galaxy.

Orion Nebula is 1344 ly away from Earth. Alpha centauri is 4.36 ly away from earth. Pluto is about 28 AU away from Earth and Sun is 1 AU distance away.

4 0

2 years ago