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3 years ago

Use the image below to answer the following question (ruler not to scale).

Physics

2 answers:

maks197457 [2]3 years ago

7 0

Answer:

Yes, they are correct, you need to include all parts of the question, don't just copy and paste the words. But in the diagram that was supposed to be there, the magnets' north poles are facing each other. Therefore they would push away from each other if they were to get any closer. So, the magnetic potential energy would decrease due to their movement away from each other. So your answer is (C. It will decrease.

Explanation:

Svetradugi [14.3K]3 years ago

4 0

Answer:

it depends on wether the + and - are facing eachother

or away from eachother

Explanation:

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Fill in the blank.

BabaBlast [244]

Answer:B

Explanation:The earth will keep moving unless acted up on by a force.

4 0

4 years ago

An electric model train is accelerated at a rate of 8 m/s^2 by a 12 N force? What is the

jok3333 [9.3K]

Answer:

m = 1.5 kg

Explanation:

Data:

Aceleration (a) = 8 m/s²
Force (F) = 12 N
Mass (m) = ?

Use formula:

$\boxed{m = \frac{F}{a}}$

Replace in the formula:

$\boxed{m = \frac{12N}{8\frac{m}{s^{2}}}}$

Equate the newtons:

$\boxed{m = \frac{12kg*\frac{m}{s^{2}}}{8\frac{m}{s^{2}}}}$

Simplify m/s²:

$\boxed{m = \frac{12kg}{8}}$

It divides:

$\boxed{m =1.5kg}$

What is the mass of the train?

The mass of the train is <u>1.5 kilograms.</u>

4 0

3 years ago

I need help PLEASE HEEEEEEEEELPP

lana66690 [7]

Answer:

a = (v2 - v1) / t

From A to B (8 - 4) m/s / 1 s = 4 m / s^2

From A to D ( 7 - 4) m/s / 5 s = .6 m / s^2

Note these equations hold for "uniform" values

They say nothing about the acceleration at intermediate points - the equation just says that his average speed increased from 4 m/s to 7 m/s during a 5 sec period

6 0

3 years ago

Consider a bicycle wheel to be a ring of radius 30 cm and mass 1.5 kg. Neglect the mass of the axle and sprocket. If a force of

Charra [1.4K]

To solve the problem it is necessary to apply the Torque equations and their respective definitions.

The Torque is defined as,

$\tau = I \alpha$