2 years ago

HELP PLS HURRY !!!!!!!!!

Physics

1 answer:

kirza4 [7]2 years ago

4 0

The answer is Electrical Energy

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wlad13 [49]

The correct answer is Ammonia

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2 years ago

What vertical distance Δy does a free-falling particle travel from the moment it starts to the moment it reaches a speed of 7.9

mr_godi [17]

Answer:

3.2 m

Explanation:

The equation to use to solve this problem is:

$v_f^2 = v_i^2 + 2 a \Delta y$

where

$v_f$ is the final velocity

$v_i$ is the initial velocity

a is the acceleration

$\Delta y$ is the distance covered

For the particle in free-fall in this problem, we have

$v_i = 0$ (it starts from rest)

$v_f = 7.9 m/s$

$g=9.8 m/s^2$ (acceleration due to gravity)

By re-arranging the equation, we can find the distance travelled:

$\Delta y = \frac{v_f^2 -v_i^2}{2a}=\frac{(7.9 m/s)^2-0^2}{2(9.8 m/s^2)}=3.2 m$

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2 years ago

Which equation describes the sum of the vectors plotted below?

worty [1.4K]

Answer:

It's the third one in the picture ...

r = 3x - 2y

Explanation:

5 0

2 years ago

Plzzz someone help me!!!!.

Vlad [161]

Answer:

He could re read his answear.

Explanation:

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2 years ago

I need help with this work

san4es73 [151]

What work??? I don’t see anything

7 0

2 years ago

Read 2 more answers