Given that:
spring compressed ( x) = 0.2 m
Work (W) = 24 J
determine , spring constant (x)=?
We know hat ,
Work (W) = (1/2). k.x²
24 = 1/2 ( k × 0.2²)
48 = k × 0.2²
<em> k = 1200 N/m</em>
A. A clastic Sedimentary rock
Answer:
the charge of the particle is 2.47 x 10⁻¹⁹ C
Explanation:
Given;
mass of the particle, m = 6.64 x 10⁻²⁷ kg
velocity of the particle, v = 8.7 x 10⁵ m/s
strength of the magnetic field, B = 1.3 T
radius of the circle, r = 18 mm = 1.8 x 10⁻³ m
The magnetic force experienced by the charge is calculated as;
F = ma = qvB
where;
q is the charge of the particle
a is the acceleration of the charge in the circular path

Therefore, the charge of the particle is 2.47 x 10⁻¹⁹ C