565,900 seconds into days

A railroad handcar is moving along straight, frictionless tracks with negligible air resistance. In the following cases, the car

viktelen [127]

This question is not complete, the complete question is;

A railroad handcar is moving along straight, frictionless tracks with negligible air resistance.

In the following cases, the car initially has a total mass (car and contents) of 170 kg and is traveling east with a velocity of magnitude 4.60 m/s.

Find the final velocity of the car in each case, assuming that the handcar does not leave the tracks.

Part A

An object with a mass of 22.0 kg is thrown sideways out of the car with a speed of 2.50 m/s relative to the car's initial velocity.

Part B

An object with a mass of 22.0 kg is thrown backward out of the car with a velocity of 4.60 m/s relative to the initial motion of the car.

Answer:

Part A) the final velocity of the car is 4.6 m/s

Part B) the final velocity of the car is 5.28 m/s

Explanation:

Given the data in the question;

Total mass (m₁+m₂) = 170 kg

velocity of magnitude Vx = 4.60 m/s

PART A)

An object with a mass of 22.0 kg is thrown sideways out of the car with a speed of 2.50 m/s relative to the car's initial velocity,

i.e

m₂ = 22.0 kg

so m₁ = 170 - 22 = 148 kg

so, we apply conservation of momentum

since the object thrown out of the car, it has nothing to do with the car's velocity.

(m₁+m₂)Vx = m₁Vx₁ + m₂Vx₂

we substitute

(170)4.60 = 148Vx₁ + 22(4.60)

782 = 148Vx₁ + 101.2

148Vx₁ = 782 - 101.2

148Vx₁ = 680.8

Vx₁ = 680.8 / 148

Vx₁ = 4.6 m/s

Therefore, the final velocity of the car is 4.6 m/s

Part B)

An object with a mass of 22.0 kg is thrown backward out of the car with a velocity of 4.60 m/s relative to the initial motion of the car.

Vx = V(m₁+m₂) / ((m₁+m₂) - m₁)

we substitute

Vx = 4.60(170) / ((170) - 22)

Vx = 782 / 148

Vx = 5.28 m/s

Therefore, the final velocity of the car is 5.28 m/s

7 0

3 years ago

Which changes of state occur between solids and gases ?

Reil [10]

Changes of State: Solids, Liquids, and Gases. A snowman, glass of water and steam might look very different but they are made of the same stuff! Just like any substance, water can exist in three different forms, called states: solid, liquid and gas. The state will change when the substance is heated.

5 0

4 years ago

Read 2 more answers

What would cause rain showers to continue over a particular area for several days?

Aloiza [94]

I think is a high-pressure system because it is only in one particular area.

5 0

4 years ago

Read 2 more answers

Imagine a star very similar to our own Sun in both size and mass. This star moves very slightly back and forth in the sky once e

Inessa05 [86]

Answer:

(c) The planet must have a mass about the same as the mass of Jupiter,

(d) The planet must be closer to the star than Earth is to the Sun.

Explanation:

Astrometry is the ideal method to detect high-mass planets that are close to their star. That is because the gravitational effect that it will have the planet over its host star will be greater. This effect can be seen as a wobble in the star as a consequence of how they orbit a common center of mass¹. The center of mass will be closer to the most massive object, So, in the case of an extrasolar planet with masses like Jupiter (Jovian), this point will be a little bit farther from the star, making the wobble more notable than in a system with a low-mass planet.

Key terms:

Astrometry: study of the position of the stars over time in the sky.

¹Center of mass: a geometrical point in which the mass from a whole system is summed.

6 0

3 years ago

A 200 kg roller coaster is located at the top of a hill where the height is 30 m. What is the velocity when it reches the bottom

maw [93]

Assuming it starts at rest, the roller coaster only has potential energy at the top of the hill, which is

$E_P=(200\,\mathrm{kg})(30\,\mathrm m)g$

When it reaches the bottom, its potential energy will have converted to kinetic energy,

$E_K=\dfrac12(200\,\mathrm{kg})v^2$

where $v$ is its velocity at that point. By the law of conservation of energy, assuming no loss of energy due to other sources (e.g. sound, heat), we have

$E_P=E_K\iff(6000\,\mathrm{kg}\cdot\mathrm m)g=(100\,\mathrm kg})v^2$

$\implies v=\sqrt{60g}\,\dfrac{\rm m}{\rm s}\approx24.2\,\dfrac{\rm m}{\rm s}$

8 0

3 years ago

Read 2 more answers

565,900 seconds into days​

565,900 seconds into days