565,900 seconds into days
1 answer:
You might be interested in
Answer:
and
Explanation:
Given:
- first charge,
- second charge,
- position of first charge,
- position of second charge,
Now since there are only 2 charges and of the same sign so they repel each other. This repulsion will be zero at some point on the line joining the charges.
<u>Now, according to the condition, electric field will be zero where the effects of field due to both the charges is equal.</u>
- since first charge is greater than the second charge so we may get a point to the right of the second charge and the distance between the two charges is 1 meter.
Since we have assumed that the we may get a point to the right of second charge so we calculate with respect to the origin.
and
Car X traveled 3d distance in t time. Car Y traveled 2d distance in t time. Therefore, the speed of car X, is 3d/t, the speed of car Y, is 2d/t. Since speed is the distance taken in a given time.
In figure-2, they are at the same place, we are asked to find car Y's position when car X is at line-A. We can calculate the time car X needs to travel to there. Let's say that car X reaches line-A in t' time.
Okay, it takes t time for car X to reach line-A. Let's see how far does car Y goes.
We found that car Y travels 2d distance. So, when car X reaches line-A, car Y is just a d distance behind car X.