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Radda [10]
4 years ago
6

565,900 seconds into days​

Physics
1 answer:
alukav5142 [94]4 years ago
4 0

Answer:

6

Explanation:

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3. Same questions as the previous problem, but for mass m just falling 3 meters in a vacuum: (a) How long does it take mass m to
sveticcg [70]

Answer:

a) 0.78 s

b) 58.86m/s'

c) Galileo's law of free fall

Explanation:

a) x = v_{i}t + \frac{1}{2}at^{2} \\3 = 0*t+\frac{1}{2} *9.81*t^{2}\\t=\sqrt{\frac{6}{9.81} }

b)At the bottom:

kinetic energy = potential energy

\frac{1}{2}mv^{2} = mgh\\ v^{2} =2*9.81*3=58.86m/s downwards

c) Galileo's law of free fall says regardless of the masses, bodies in a vacuum will fall, on the earth, at the same acceleration

3 0
3 years ago
Q2. You push a crate up a ramp with a force of 10 N. Despite your pushing, the crate slides down the ramp 4 m. How much work did
Ksivusya [100]

Answer:

40 J

Explanation:

From the question given above, the following data were obtained:

Force (F) = 10 N

Distance (s) = 4 m

Workdone (Wd) =?

Work done is simply defined as the product of force and distance moved in the direction of the force. Mathematically, we can express the Workdone as:

Workdone = force × distance

Wd = F × s

With the above formula, we can obtain the workdone as follow:

Force (F) = 10 N

Distance (s) = 4 m

Workdone (Wd) =?

Wd = F × s

Wd = 10 × 4

Wd = 40 J

Thus, 40 J of work was done.

5 0
3 years ago
A plane is flying east at 115 m/s. The wind accelerates it at 2.88 m/s^2 directly northwest. After 25.0s, what is the magnitude
kondaur [170]

Answer:

81.8 m/s

Explanation:

The initial velocity of the plane is:

v_0=115 m/s (toward east)

So, decomposing along the x- and y- directions:

v_{x0} = 115 m/s\\v_{y0} = 0

(we took east as positive x-direction and north as positive y-direction)

The acceleration is

a=2.88 m/s^2 (northwest, so the angle with the positive x-direction is 135 degrees)

Decomposing it along the two directions:

a_x = a cos 135^{\circ} = (2.88 m/s^2)(cos 135^{\circ})=-2.04 m/s^2\\a_y = a sin 135^{\circ} = (2.88 m/s^2)(sin 135^{\circ})=2.04 m/s^2

So the two components of the velocity after a time t = 25.0 s will be

v_x = v_{x0} + a_x t = 115 m/s + (-2.04 m/s^2)(25.0 s)=64 m/s\\v_y = v_{y0} + a_y t = 0 m/s + (2.04 m/s^2)(25.0 s)=51 m/s

So, the magnitude of the velocity of the plane will be

v=\sqrt[v_x^2+v_y^2}=\sqrt{(64 m/s)^2+(51 m/s)^2}=81.8 m/s

6 0
3 years ago
What happens when light is allowed to pass through a suspension
Nutka1998 [239]

Answer:

When light is passed through a true solution, the dissolved are too small to deflect light. suspensions may scatter light, but if the number of suspended particles is sufficiently large, the suspension may simply be opaque, and the light scattering would not occur.

3 0
4 years ago
Read 2 more answers
Hunter wants to measure the weight of a dumbbell. He should
MissTica
Use a scale and record the weight in cm^3
4 0
3 years ago
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