Answer:
77000 J
Explanation:
Formula for the heat energy is;
Q = m•c•Δt
We are given;
mass; m = 2 kg
Change in temperature; Δt = 110 - 10 = 100 °C
From online values, specific heat capacity of copper is; c = 385 J/kg.°C
Thus;
Q = 2 × 100 × 385
Q = 77000 J
This is an experiment that explains the Bernoulli principle. According to this principle, at the bottom of the spoon, there will be a reduction in pressure.
<h3>Explanation of the Bernoulli principle</h3>
So the pressure at the bottom of the spoon reduces because the velocity of the water is larger and the height of the column of water is smaller at this part.
So the spoon is attracted to the water at the point of lowest pressure because objects gravitate to low-pressure points.
Learn more about the Bernoulli Principle at:
brainly.com/question/24623919
Answer:
is the height of the TV screen.
Explanation:
Given:
diagonal of TV screen, ![d=40\ in](https://tex.z-dn.net/?f=d%3D40%5C%20in)
width of TV scree, ![w=32\ in](https://tex.z-dn.net/?f=w%3D32%5C%20in)
As we know that the TV screen is rectangular in shape so including its height and with along with the diagonal forms a right angled triangle in which the diagonal is the hypotenuse of the triangle formed so.
![h=\sqrt{d^2-w^2}](https://tex.z-dn.net/?f=h%3D%5Csqrt%7Bd%5E2-w%5E2%7D)
![h=\sqrt{40^2-32^2}](https://tex.z-dn.net/?f=h%3D%5Csqrt%7B40%5E2-32%5E2%7D)
is the height of the TV screen.
Missing graph. I attach it in the answer.
In a uniformly accelerated motion, the velocity at time t is given by:
![v(t)=at](https://tex.z-dn.net/?f=v%28t%29%3Dat)
where a is the acceleration and t is the time.
Given the previous equation, if we plot v(t) versus t, we find a straight line; moreover, a (the acceleration) represents the slope of the curve.
Looking at the graph, we see that when the time goes from 10 s to 20 s, the velocity increases from 4 m/s to 6 m/s. Therefore the slope of the curve is
![a= \frac{\Delta v}{\Delta t}= \frac{6 m/s-4 m/s}{20 s-10 s}= \frac{2 m/s}{10 s}=0.2 m/s^2](https://tex.z-dn.net/?f=a%3D%20%5Cfrac%7B%5CDelta%20v%7D%7B%5CDelta%20t%7D%3D%20%5Cfrac%7B6%20m%2Fs-4%20m%2Fs%7D%7B20%20s-10%20s%7D%3D%20%5Cfrac%7B2%20m%2Fs%7D%7B10%20s%7D%3D0.2%20m%2Fs%5E2%20%20%20)
and this corresponds to the acceleration.
So, the correct answer is <span>
0.2 m/s2.</span>
Answer:
the time of motion of the ball is 6.89 ms.
Explanation:
Given;
angular speed, ω = 38 rad/s
angular distance, θ = 15 degrees
Angular distance in radian;
![\theta = 15^0 \times\frac{2\pi \ rad}{360^0} = 0.2618 \ rad](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2015%5E0%20%5Ctimes%5Cfrac%7B2%5Cpi%20%5C%20rad%7D%7B360%5E0%7D%20%3D%200.2618%20%5C%20rad)
Time of motion is calculated as;
![time = \frac{angular \ distance}{angular \ speed} \\\\t= \frac{\theta}{\omega} = \frac{0.2618 \ rad}{38 \ rad/s} \\\\t = 6.89 \ \times 10^{-3} \ s\\\\t = 6.89 \ ms](https://tex.z-dn.net/?f=time%20%3D%20%5Cfrac%7Bangular%20%5C%20distance%7D%7Bangular%20%5C%20speed%7D%20%5C%5C%5C%5Ct%3D%20%5Cfrac%7B%5Ctheta%7D%7B%5Comega%7D%20%3D%20%5Cfrac%7B0.2618%20%5C%20rad%7D%7B38%20%5C%20rad%2Fs%7D%20%5C%5C%5C%5Ct%20%3D%206.89%20%5C%20%5Ctimes%2010%5E%7B-3%7D%20%5C%20s%5C%5C%5C%5Ct%20%3D%206.89%20%5C%20ms)
Therefore, the time of motion of the ball is 6.89 ms.