Answer: The concentration of hydrogen ions for this solution is  .
.
Explanation:
Given: pOH = 11.30
The relation between pH and pOH is as follows.
pH + pOH = 14
pH + 11.30 = 14
pH = 14 - 11.30
= 2.7
Also, pH is the negative logarithm of concentration of hydrogen ions.
![pH = - log [H^{+}]](https://tex.z-dn.net/?f=pH%20%3D%20-%20log%20%5BH%5E%7B%2B%7D%5D)
Substitute the values into above formula as follows.
 ![pH = -log [H^{+}]\\2.7 = -log [H^{+}]\\conc. of H^{+} = 1.99 \times 10^{-3}](https://tex.z-dn.net/?f=pH%20%3D%20-log%20%5BH%5E%7B%2B%7D%5D%5C%5C2.7%20%3D%20-log%20%5BH%5E%7B%2B%7D%5D%5C%5Cconc.%20of%20H%5E%7B%2B%7D%20%3D%201.99%20%5Ctimes%2010%5E%7B-3%7D)
Thus, we can conclude that the concentration of hydrogen ions for this solution is  .
.
 
        
             
        
        
        
Answer:
It’s true
Explanation:
If we account for all reactants and products in a chemical reaction, the total mass will be the same at any point in time in any closed system. ... The Law of Conservation of Mass holds true because naturally occurring elements are very stable at the conditions found on the surface of the Earth.
 
        
             
        
        
        
<span>If I done the math correctly it is 3729J because you multiply 16.5 g  by the 2260 J/g and get 3729 J</span>
        
             
        
        
        
Answer:
Distillation and using Chromatography
Explanation:
Distillation:
based on using boiling point. 
Ex: separating a mixture of water and sugar by boiling the water away.
Chromatography:
based on absorption
Ex: separating the different colours that make up a black marker
 
        
             
        
        
        
Answer:
The answer is "Choice A and Choice B"
Explanation:
The Zero-Order reactions are usually found if a substrate, like a surface or even a catalyst, is penetrated also by reactants. Its success rate doesn't depend mostly on the amounts of the various reaction in this reaction.
Let the Rate = k
As  doesn't depend on reaction rate, a higher reaction rate does not intensify the reaction.
 doesn't depend on reaction rate, a higher reaction rate does not intensify the reaction.
By the rate  the created based and the reaction rate is about the same.
 the created based and the reaction rate is about the same.