Answer:
1461.7 g of AgI
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
CaI₂ + 2AgNO₃ —> 2AgI + Ca(NO₃)₂
From the balanced equation above,
1 mole of CaI₂ reacted to produce 2 moles of AgI.
Next, we shall determine the number of mole AgI produced by the reaction of 3.11 moles of CaI₂. This can be obtained as follow:
From the balanced equation above,
1 mole of CaI₂ reacted to produce 2 moles of AgI.
Therefore, 3.11 moles of CaI₂ will react to produce = 3.11 × 2 = 6.22 moles of AgI
Finally, we shall determine the mass of 6.22 moles of AgI. This can be obtained as follow:
Mole of AgI = 6.22 moles
Molar mass of AgI = 108 + 127
= 235 g/mol
Mass of AgI =?
Mass = mole × molar mass
Mass of AgI = 6.22 × 235
Mass of AgI = 1461.7 g
Therefore, 1461.7 g of AgI were obtained from the reaction.
Answer:
6,613 M
Explanation:
Dilution is the process of reducing the concentration of a solute in solution, mixing initial solution with more solvent.
The concentration of Solution B is:
23,881 M × = 9,552 M
Because the initial eight parts are diluted to 12+8 parts.
Thus, concentration of solution C is:
9,552 M × = 6,613 M
I hope it helps!
The potential energy of the products is higher than the potential energy of the reactants.
Answer:
Float
Explanation:
If the weight of liquid displaced and the weight of an object are the same, the object will float in the liquid.
From Archimedes principle, when an object is immersed in fluid, a force called upthrust supports it and it equal to the weight of the liquid displaced.
When in a liquid, the weight of the liquid displaced is the same as that of the of the object, it will float and not sink.
