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Musya8 [376]
2 years ago
5

The half-life of thorium-227 is 18.72 days. How many days are required for three-fourths of a given amount to decay?

Chemistry
1 answer:
Pie2 years ago
7 0
T½=18.72days
therefore t¾=18.72+½ of 18.72
we have 18.72+9.36=28.08days
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Which of the following substances would likely dissolve but not dissociate in water
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Answer:

Oils, fats, and certain organic solvents do not dissolve in water because they are hydrophobic.

Explanation:

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A solution containing 60 grams of nano3 completely dissolved in 50. Grams of water at 50°c is classified as being
Igoryamba

Answer:

<em>A solution containing 60 grams of nano3 completely dissolved in 50. Grams of water at 50°c is classified as being</em> <u>supersaturaded</u>

Explanation:

This question is about solubility.

Regarding solubility, the solutions may be classified as:

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  • Saturated: the concentration is the maximum permitted at the given temperature, under normal conditions.

  • Supersaturated: the concentration has overcome the maximum permitted at the given temperature. This is possible only under special conditions and is a very unstable state.

Each substance has its own, unique solubility properties. So, in order to tell the state of the solution you need to compare with either solubility tables, or solubility curves; or run you own experiments.

  • In internet you can find the solubility curve of NaNO₃ showing the solubility for a wide range of temperatures.

  • In such curve the solubility of NaNO₃ at 50°C is about 115 g of NaNO₃ per 100 g  of water.

  • Hence, do the proportion to determine the amount of solute that can be dissolved in 50 grams of water at 50°CÑ

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  • <u>Conclusion</u>: 50 grams of water can contain 57.5 g of NaNO₃ dissolved; so, <em>a solution containing 60 g of NaNO₃ completely dissolved in 50 grams of water is supersaturated.</em>

<em />

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3 years ago
If a person did overshoot the endpoint, would this cause the experimental value for the % of acid in vinegar to be too high or t
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7 0
3 years ago
A 5.00-cm cube of magnesium has a mass of 217.501 g. What is the density of magnesiummetal?
Doss [256]

Answer:

d = 43.5 g/cm³

Explanation:

Given data:

Mass of magnesium cube = 217.501 g

Volume of magnesium cube = 5.00 cm³

Density of magnesium cube = ?

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Formula:

d = m/v

d = density

m = mass

v = volume

by putting values,

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d = 43.5 g/cm³

8 0
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