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Gekata [30.6K]
2 years ago
10

What lump sum of money must be deposited in a bank account at present time so that Php 500 monthly can be withdrawn for five yea

rs with the first withdrawal scheduled six years from today? Interest rate is 9% compounded quarterly.​
Engineering
1 answer:
jenyasd209 [6]2 years ago
3 0

Using compound interest, it is found that a sum of $16,586.26 must be deposited.

<h3>What is compound interest?</h3>

The amount of money earned, in compound interest, after t years, is given by:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

In which:

  • A(t) is the amount of money after t years.
  • P is the principal(the initial sum of money).
  • r is the interest rate(as a decimal value).
  • n is the number of times that interest is compounded per year.
  • t is the time in years for which the money is invested or borrowed.

In this problem:

  • We want to have Php 500 to be withdrawn monthly for 5 years, hence A(t) = 500 x 12 x 5 = 30000.
  • The first withdraw is 6 years from now, hence t = 6.
  • The interest rate is of r = 0.09.
  • Compounded quarterly, hence n = 4.

The amount deposited is the principal, hence:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

30000 = P\left(1 + \frac{0.09}{4}\right)^{4(6)}

(1.025)^{24}P = 30000

P = \frac{30000}{(1.025)^{24}}

P = 16586.26

A sum of $16,586.26 must be deposited.

To learn more about compound interest, you can take a look at brainly.com/question/25781328

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topjm [15]

Answer:

a) the moisture content before it was placed in the oven is 18.18%

b) degree of saturation for soil is 72.19%

Explanation:

Given the data in the question;

Moisture Content = [(Weight of soil before dry - dry weight) / dry weight] × 100

so we substitute

Moisture content = [(53.3 - 45.1) / 45.1 ] × 100

= (8.2/45.1) × 100

= 18.18%

Therefore the moisture content before it was placed in the oven is 18.18%

Dry Unit Weight = dry weight / volume

Dry Unit Weight = 45.1 lb / 0.45 ft³

Dry Unit Weight = 100.22 lb/ft³

we know that;

dry unit weight = (Specific gravity × unit weight of water) / (1 + e)

we also know that; unit weight of water is 62.43 lbf/ft³

so we substitute

e = (2.70×62.43 / 100.22) - 1

e = 1.68 - 1

e = 0.68

so void ratio e = 0.68

Now we determine the degree of saturation using the equation;

degree of saturation = (Moisture content × specific gravity) / void ratio

we substitute

degree of saturation = ( 18.18% × 2.7) / 0.68

= 0.49086 / 0.68

= 0.7219 ≈ 72.19%

Therefore degree of saturation for soil is 72.19%

7 0
3 years ago
The engine of a 2000kg car has a power rating of 75kW. How long would it take (seconds) to accelerate from rest to 100 km/hr at
Delvig [45]

Answer: 10.29 sec.

Explanation:

Neglecting drag and friction, and at road level , the energy developed during the time the car is accelerating, is equal to the change in kinetic energy.

If the car starts from rest, this means the following:

ΔK = 1/2 m*vf ²

As Power (by definition) is equal to Energy/Time= 75000 W= 75000 N.m/seg, in order to get time in seconds, we need to convert 100 km/h to m/sec first:

100 (Km/h)*( 1000m /1 Km)*(3600 sec/1 h)= 27,78 m/sec

Now, we calculate the change in energy:

ΔK= 1/2*2000 Kg. (27,78)² m²/sec²= 771,728 J

<h2>If P= ΔK/Δt, </h2><h2>Δt= ΔK/P= 771,728 J / 75,000 J/sec= 10.29 sec.</h2>
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3 years ago
If i build thing a and thing a builds thing b did i build thing b
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Answer:

<h3>Yes</h3>

Explanation:

If you build thing "a" and thing "a" builds thing "b" you <u>indirectly</u> build thing "b".

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