3 years ago

How much energy in joule is added to a 12 g of sample of aluminum (c=0.897 J/g ◦C) to raise the temperature from 20 ◦C to 45 ◦C?

Engineering

1 answer:

MArishka [77]3 years ago

8 0

Answer:

269.1J

Explanation:

m = 12g

c = 0.897J/g°C

∆T = 45 - 20 = 25°C

H = mc∆T = 12 × 0.897 × 27 = 269.1J

You might be interested in

Prefix version of 6600 volts

GenaCL600 [577]

Answer:

6.6 kilo volts = 6.6 k volts

Explanation:

A prefix is a word, number or a letter that is added before another word. In physics we have different prefixes for the exponential powers of 10, that are placed before units in place of those powers. Some examples are:

deci (d) ------ 10⁻¹

centi (c) ------ 10⁻²

milli (m) ------ 10⁻³

kilo (k) ------ 10³

mega (M) ----- 10⁶

giga (G) ------ 10⁹

We have:

6600 volts

converting to exponential form:

=> 6.6 x 10³ volts

Thus, we know that the prefix of kilo (k) is used for 10³.

Hence,

=> <u>6.6 kilo volts = 6.6 k volts</u>

7 0

3 years ago

Use the concept that y = c, −[infinity] < x < [infinity], is a constant function if and only if y' = 0 to determine whethe

attashe74 [19]

Answer:

attached below

Explanation:

5 0

3 years ago

All of these are uses of microwaves except...

Talja [164]

Answer:D

Explanation:

5 0

3 years ago

A safety interlock module operates by monitoring the voltage from the

In-s [12.5K]

Answer: its an Ignition coil

8 0

3 years ago

For an isotropic material, E and ν are often chosen as the two independent engineering constants. There are other elastic consta

pav-90 [236]

Answer:

khgy

Explanation:

nbv

8 0

3 years ago