Answer:
Q = 62 ( since we are instructed not to include the units in the answer)
Explanation:
Given that:



Q = ???
Now the gas expands at constant pressure until its volume doubles
i.e if 
Using Charles Law; since pressure is constant




mass of He =number of moles of He × molecular weight of He
mass of He = 3 kg × 4
mass of He = 12 kg
mass of Ar =number of moles of Ar × molecular weight of Ar
mass of He = 7 kg × 40
mass of He = 280 kg
Now; the amount of Heat Q transferred = 
From gas table

∴ Q = 
Q = 
Q = 62 MJ
Q = 62 ( since we are instructed not to include the units in the answer)
Answer:
Total BF for the interior wall is 7.50BD
Explanation:
Given Data:
· Size of stud = 2” x 6”
· Height of Wall = 8 ft
· Top plates = 2
· Bottom Plate = 1
BF stands for board feet in lumber/wood terminology. It is the unit of volume.
1 BF (Board feet) = 1 ft x 1 ft x 1 inch
Since there are total three plates at top and bottom, we have to deduct their thickness from wall height to calculate height of stud.
Height of stud = 8’ – 3 x 2” = 7’6” = 7.5 ft
Board feet of one stud = 7.50 6/12 x 2 = 7.50 BD
Total BF for the interior wall is 7.50BD
Answer:D
Explanation:
Take longer time to retrieve than long term memory, involves transient modifications in the function of pre existing synapses, such as channel modifications.
Answer:
Qx = 9.10
m³/s
Explanation:
given data
diameter = 85 mm
length = 2 m
depth = 9mm
N = 60 rev/min
pressure p = 11 ×
Pa
viscosity n = 100 Pas
angle = 18°
so Qd will be
Qd = 0.5 × π² ×D²×dc × sinA × cosA ..............1
put here value and we get
Qd = 0.5 × π² × ( 85
)²× 9
× sin18 × cos18
Qd = 94.305 ×
m³/s
and
Qb = p × π × D × dc³ × sin²A ÷ 12 × n × L ............2
Qb = 11 ×
× π × 85
× ( 9
)³ × sin²18 ÷ 12 × 100 × 2
Qb = 85.2 ×
m³/s
so here
volume flow rate Qx = Qd - Qb ..............3
Qx = 94.305 ×
- 85.2 ×
Qx = 9.10
m³/s