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densk [106]
2 years ago
9

Identify the products of this single-replacement reaction between sulfuric acid and aluminum. Then balance the equation. (2 poin

ts)
___H₂SO₄ + ___Al → ___ + ___
Chemistry
1 answer:
jeka942 years ago
7 0

The products of this reaction between aluminum and sulfuric acid are two: hydrogen and aluminum sulfate.

<h3>What are the products in a reaction?</h3>

This concept refers to the substances obtained at the end of the reaction.

<h3>What does it mean to balance an equation?</h3>

It means to make sure there are the same molecules in the reactants and products.

<h3>What are the products in this reaction?</h3>
  • Al + H2SO4 = Al2 (SO4)3 + H2  
  • Al2 (SO4)3 = Aluminium sulfate
  • H = Hydrogen

<h3>What is the balanced equation?</h3>

2Al + 3H2SO4 = Al2 (SO4)3 + 3H2

Learn more about chemical reaction in: brainly.com/question/3461108

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A sample of chromium oxide is 76.5hromium by weight. what is the simplest formula of the oxide?
otez555 [7]

CrO and Cr₂O₃ make up the simplest chromium oxide formula.

What name does Cr₂O₃ use?

  • Chromium oxide (Cr₂O₃)sometimes referred to as chromium sesquioxide or chromic oxide, is a compound in which chromium is oxidized to a +3 state. Sodium dichromate is calcined with either carbon or sulfur to produce it.
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6 0
1 year ago
What is the volume of 3.89 grams of helium gas?
lukranit [14]

Answer: There are 971.77 millimoles in 3.89 grams of Helium

Explanation:

i think its right im not really sure

7 0
3 years ago
If the density of an ideal gas at stp if found to be 0.0902 g/l, what is its molar mass?
lisabon 2012 [21]
P=0.0902 g/l
v=22.4 l/mol   (stp)

M=vp

M=22.4 l/mol * 0.0902 g/l=2.020 g/mol

M=2.020 g/mol
4 0
3 years ago
Read 2 more answers
Where is the kinetic energy GREATEST?
Zarrin [17]
Kinetic Energy is greatest at the bottom of the highest point
4 0
3 years ago
What is the empirical formula for a compound that contains 10.89% magnesium 31.77% chloride and 57.34% oxygen
Blizzard [7]

Answer: Mg_{1}Cl_{2}O_{8}

Explanation:

If percentage are given then we are taking total mass is 100 grams.So, the mass of each element is equal to the percentage given.

Mass of Mg = 10.89 g

Mass of Cl = 31.77 g

Mass of O = 57.34 g

Step 1 : convert given masses into moles.

Moles of Mg=\frac {\text{ given mass of Mg}}{\text{ molar mass of Mg}}= \frac {10.89g}{24g/mole}=0.45moles

Moles of Cl = \frac {\text{ given mass of Cl}}{\text{ molar mass of Cl}}= \frac {31.77g}{35.5g/mole}=0.89moles

Moles of O =\frac {\text{ given mass of O}}{\text{ molar mass of O}}=\frac {57.34g}{16g/mole}=3.58moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Mg = \frac {0.45}{0.45}=1

For Cl = \frac {0.89}{0.45}=2

For O= \frac {3.58}{0.45}=8

The ratio of Mg :Cl : O= 1 : 2 : 8

Hence the empirical formula is Mg_{1}Cl_{2}O_{8}

4 0
3 years ago
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