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ruslelena [56]
3 years ago
5

Two samples of carbon come into contact. Heat will transfer from Sample A to Sample B if the average kinetic energy of Sample A'

s atoms is ___ the average kinetic energy of Sample B's atoms.
A.greater than
B.less than
C.equal to
Chemistry
2 answers:
Gennadij [26K]3 years ago
4 0
A. Higher average kinetic energy translates to higher temperature. Heat flows from a region of higher temperature to a region of lower temperature.
Doss [256]3 years ago
3 0

Answer : (A) greater than

Explanation :

we know that every objects have some energy. It can be kinetic, potential, vibration or rotation. According to the first law of thermodynamics, energy can neither be created nor destroyed but it converts into one form to another.

Kinetic energy is related with the motion of atoms or molecules.

In the chemical reaction, the reactant molecules converted into product molecules when there will be a effective collision between the reactant molecules and for the effective collision of the molecules, the molecules requires kinetic energy.

Average kinetic energy formula is,

K=\frac{3}{2}\times nRT

where,

K = Average kinetic energy

n = Number of moles

R = Gas constant

T = temperature

According to the formula, the average kinetic energy is directly proportional to the temperature. Average kinetic energy depends on the temperature. This means that when the temperature of the molecule is high then the average kinetic energy of the molecule is high.

When heat flow from system (1) to another system (2) this means that the temperature will be more in system (1) as compared to system (2). And as we know that the kinetic energy is depend on temperature, the average kinetic energy is more in system (1) as compared to system (2).

when the heat transfer from sample A to sample B, the average kinetic energy of sample A is greater than the average kinetic energy of the sample B.


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Phenol red is an indicator that changes color over a range from ph=6.4 to ph=8.0. what is ka of phenol red?
patriot [66]
First, we will get the average pH of the two given values:
average pH = (6.4+8) / (2) = 7.2
At this average pH, the concentration of the acid from the phenol red is equal to the concentration of the base.
pH = 7.2
[H+] = 10^(-7.2) = 6.3 * 10^-8

Phenol red has the general formula HA, this gives us:
HA <.......> H+ + A- 
At pH = 7.2, [H+] = [A-]
<span>Ka = [H+][A-]/ [HA]
</span>Ka = [H+] = <span>6.3 x 10^-8</span>

7 0
3 years ago
A sample of 19 mg of 9-fluorenone is dissolved in 5 mL of diethyl ether. The resulting organic
maks197457 [2]

Answer:

15.70mg would remain

Explanation:

Partition coefficient is used to extract or purify a solute from a solvent selectively to avoid interference from other substances. For the problem, formula is:

Kp = Concentration 9-fluorenone in ether / Concentration of solute in H₂O

After the solute, 9-fluorenone, is extracted with water, the mass that remains in ether is:

(19mg - X)

<em>Where X is the mass that now is in the aqueous phase</em>

Replacing in Kp formula:

9.5 = (19mg - X) / 5mL / (X /10mL)

0.95X = 19mg - X / 5mL

4.75X = 19 - X

5.75X = 19

X = 19 / 5.75

X = 3.30mg

That means 9-fluorenone that remain in the ether layer is:

19mg - 3.30mg =

<h3>15.70mg would remain</h3>
8 0
3 years ago
Calculate the volume of a balloon that can hold 113.4 g of nitrogen dioxide, NO2 gas at STP-
Karolina [17]

Answer:

55.18 L

Explanation:

First we convert 113.4 g of NO₂ into moles, using its molar mass:

  • 113.4 g ÷ 46 g/mol = 2.465 mol

Then we<u> use the PV=nRT formula</u>, where:

  • P = 1atm & T = 273K (This means STP)
  • n = 2.465 mol
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • V = ?

Input the data:

  • 1 atm * V = 2.465 mol * 0.082atm·L·mol⁻¹·K⁻¹ * 273 K

And <u>solve for V</u>:

  • V = 55.18 L
6 0
3 years ago
What is the vapor pressure of CS2CS2 in mmHgmmHg at 26.5 ∘C∘C? Carbon disulfide, CS2CS2, has PvapPvap = 100 mmHgmmHg at −−5.1 ∘C
Digiron [165]

Answer: 26.5 mm Hg

Explanation:

The vapor pressure is determined by Clausius Clapeyron equation:

ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}(\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1= initial pressure at 26.5^oC = ?

P_2 = final pressure at -5.1^oC = 100 mm Hg

= enthalpy of vaporisation = 28.0 kJ/mol =28000 J/mol

R = gas constant = 8.314 J/mole.K

T_1= initial temperature = 26.5^oC=273+26.5=299.5K

T_2 = final temperature =-5.1^oC=273+(-5.1)=267.9K

Now put all the given values in this formula, we get

\log (\frac{P_1}{100})=\frac{28000}{2.303\times 8.314J/mole.K}[\frac{1}{299.5}-\frac{1}{267.9}]

\log  (\frac{P_1}{100})=-0.576

\frac{P_1}{100}=0.265

P_1=26.5mmHg

Thus the vapor pressure of CS_2CS_2 in mmHg at 26.5 ∘C is 26.5

7 0
3 years ago
What contains more hydrogen atoms, 1.0 mole of H20 or 1.0 moles of НЗО?
Vladimir [108]
A mole of an element refers to 6.02e23 atoms so they would have the same amount of atoms
4 0
3 years ago
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