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ruslelena [56]
3 years ago
5

Two samples of carbon come into contact. Heat will transfer from Sample A to Sample B if the average kinetic energy of Sample A'

s atoms is ___ the average kinetic energy of Sample B's atoms.
A.greater than
B.less than
C.equal to
Chemistry
2 answers:
Gennadij [26K]3 years ago
4 0
A. Higher average kinetic energy translates to higher temperature. Heat flows from a region of higher temperature to a region of lower temperature.
Doss [256]3 years ago
3 0

Answer : (A) greater than

Explanation :

we know that every objects have some energy. It can be kinetic, potential, vibration or rotation. According to the first law of thermodynamics, energy can neither be created nor destroyed but it converts into one form to another.

Kinetic energy is related with the motion of atoms or molecules.

In the chemical reaction, the reactant molecules converted into product molecules when there will be a effective collision between the reactant molecules and for the effective collision of the molecules, the molecules requires kinetic energy.

Average kinetic energy formula is,

K=\frac{3}{2}\times nRT

where,

K = Average kinetic energy

n = Number of moles

R = Gas constant

T = temperature

According to the formula, the average kinetic energy is directly proportional to the temperature. Average kinetic energy depends on the temperature. This means that when the temperature of the molecule is high then the average kinetic energy of the molecule is high.

When heat flow from system (1) to another system (2) this means that the temperature will be more in system (1) as compared to system (2). And as we know that the kinetic energy is depend on temperature, the average kinetic energy is more in system (1) as compared to system (2).

when the heat transfer from sample A to sample B, the average kinetic energy of sample A is greater than the average kinetic energy of the sample B.


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4. What is the total mass of ice that can be vaporized by 2100 kJ of heat energy?
anygoal [31]

Answer:

5 g

Explanation:

The heat required to vaporize ice is the sum of

i) Heat required to melt ice at 0°C

ii) Heat required to raise the temperature from  0°C to 100°C

iii) Heat required to vaporize water at 100°C

Thus;

H = nLfus + ncθ + nLvap

H= n(Lfus + cθ + Lvap)

Lfus = 6.01 kJ/mol

Lvap = 41 kJ/mol

c = 75.38

n =?

2100 = n(6.01  + 75.38(100) + 41)

n = 2100 KJ/7585.01 kJ/mol

n = 0.277 moles

Mass of water = number of moles * molar mass

Mass of water = 0.277 moles * 18 g/mol

Mass of water =  5 g

3 0
3 years ago
calculate the enthalpy change for converting 1.00 mol of liquid water at 100 C to water vapor at 145 degree celsius for water Δ
Svetllana [295]

Answer:

q1 = mCpΔT

    = 18.016g × 1.84J/g.K × (418.15-373.15)

     = 1491.72 J

q2 = n×ΔH vap

     =  1mol ×44.0kJ/mol

     = 44KJ

∴ qtotal = q1+ q2

             = 1.498kJ + 44.0kJ

             = 45.498KJ

Explanation: The heat flow can be separated into steps.all that is being observed at a constant pressure,the heat flow is equal to the enthalpy.

8 0
4 years ago
What is the molar concentration of a 2 liter solution containing 200 grams of glucose?
NARA [144]

The molar concentration is 1.11M.

<h3>What is molar concentration?</h3>

The phrase "molar concentration" (also known as "molarity," "amount concentration," or "substance concentration") refers to the amount of a substance per unit volume of solution and is used to describe the concentration of a chemical species, specifically a solute, in a solution. The most frequent measure of molarity in chemistry is the number of moles per liter, denoted by the unit symbol mol/L or mol/dm3 in SI units. A solution with a concentration of 1 mol/L is referred to as 1 molar, or 1 M.

<h3>Given : </h3>

Volume of the solution = 2L

Mass of glucose given = 200g

Concentration of glucose= ?

<h3>Formula use: </h3>

Molarity = no. of moles of solute / volume of the solution (L)

Moles of solute = given mass of solute / molar mass of the solute

<h3>Solution: </h3>

No. of moles of solute( glucose ) = 200 / 180 = 1.11 moles'

Molarity = 1.11 / 2 = 0.5555 mol L ^(-1)

Therefore, the molar concentration of glucose in the solution = 0.555 mol L ^(-1)

To learn more about molar concentration :

brainly.com/question/15532279

#SPJ4

8 0
2 years ago
What compound is formed when 2,2-dimethyloxirane (2-methyl-1,2-epoxypropane) is treated with ethanol containing sulfuric acid
vladimir1956 [14]

Answer:

2-ethoxy-2-methylpropan-1-ol

Explanation:

On this reaction, we have an "<u>epoxide"</u> (2-methyl-1,2-epoxypropane). Additionally, we have <u>acid medium</u> (due to the sulfuric acid H_2SO_4). The acid medium will produce the <u>hydronium ion</u> (H^+). This ion would be attacked by the oxygen of the epoxide. Then a <u>carbocation</u> would be produced, in this case, the most stable carbocation is the <u>tertiary one</u>. Then an <u>ethanol</u> molecule acts as a nucleophile and will attack the carbocation. Finally, a <u>deprotonation </u>step takes place to produce <u>2-ethoxy-2-methylpropan-1-ol</u>.

See figure 1

I hope it helps!

3 0
3 years ago
Determine if the bond between each pair of atoms is pure covalent, polar covalent, or ionic. drag the appropriate items to their
dsp73

Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

 

                Less than 0.4 then it is Non Polar Pure Covalent

                

                Between 0.4 and 1.7 then it is Polar Covalent 

            

                Greater than 1.7 then it is Ionic

 

For Br and Br,

                    E.N of Bromine      =   2.96

                    E.N of Bromine      =   2.96

                                                   ________

                    E.N Difference             0.00         (Non Polar/Pure Covalent)

 

For N and O,

                    E.N of Oxygen      =   3.44

                    E.N of Nitrogen     =   3.04

                                                   ________

                    E.N Difference             0.40           (Non Polar/Pure Covalent)

 

For P and H,

                    E.N of Hydrogen       =   2.20

                    E.N of Phosphorous  =   2.19

                                                              ________

                    E.N Difference                  0.01          (Non Polar/Pure Covalent)

 

For K and O,

                    E.N of Oxygen          =   3.44

                    E.N of Potassium      =   0.82

                                                   ________

                    E.N Difference                2.62              (Ionic)

6 0
4 years ago
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