1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nika2105 [10]
2 years ago
15

Which of these is a benefit of nuclear fusion?

Chemistry
1 answer:
dybincka [34]2 years ago
8 0

Answer:

B. There is a lower risk of runaway chain reactions.

Explanation:

Ap Ex Confirmed

You might be interested in
Please help me it's a emergency!!!!!​
PilotLPTM [1.2K]

Answer:

probably a space probe because the sun is too hot for anything else to go on  the sun

Explanation:

8 0
2 years ago
1‑propanol ( n ‑propanol) and 2‑propanol (isopropanol) form ideal solutions in all proportions. Calculate the partial pressure a
Alex777 [14]

Answer:

y_{prop} = 0.134; y_{iso} = 0.866

The partial pressure of isopropanol = 34.04 Torr; The partial pressure of propanol = 5.26 Torr

Explanation:

For each of the solutions:

mole fraction of isopropanol  (x_{iso}) = 1 - mole fraction of propanol (x_{prop}).

Given: mole fraction of propanol = 0.247. Thus, the mole fraction of isopropanol = 1 - 0.247 = 0.753.

Furthermole, the partial pressure of isopropanol = x_{iso}*vapor pressure of isopropanol = 0.753*45.2 Torr = 34.04 Torr

The partial pressure of propanol = x_{prop}*vapor pressure of propanol = 0.247*20.9 Torr = 5.16 Torr

Similarly,

In the vapor phase,

The mole fraction of propanol (y_{prop}) = \frac{P_{prop} }{P_{prop}+P_{iso}}

Where, P_{prop} is the partial pressure of propanol and P_{iso} is the partial pressure of isopropanol.

Therefore,

y_{prop} = 5.26/(34.04+5.16) = 0.134

y_{iso} = 1 - 0.134 = 0.866

5 0
3 years ago
Can someone please help, 20 points <br> Draw 3-ethyl-2,4-dimethyl octanoic acid
Brilliant_brown [7]

3-ethyl-2.4-dimethyl-octanoic acid

6 0
2 years ago
Diamond is a natural form of pure carbon. What number of atoms of carbon are in a 1.00-carat diamond (1.00 carat = 0.200 g)?
slega [8]

Answer:

1.004×10²²

Explanation:

The molar mass of carbon is 12 g/mol

which means that:

<u>1 mole of carbon atoms has a mass of 12 grams.</u>

Since, diamond is a allotrope of carbon.

Mass of  1.00-carat diamond in grams is:

1.00 carat = 0.200 g

<u> Since, 1 mole of C contains 6.022×10²³ atoms of C</u>

So,  

12 grams contains 6.022×10²³ atoms of C

1 gram contains 6.022×10²³/ 12 atoms of C

0.200 gram contains (6.022×10²³/ 12)×0.200 atoms of C

Thus,

<u>1 carat diamond contains 1.004×10²² atoms of C.</u>

8 0
2 years ago
Determine the rate of a reaction that follows the rate law rate = k a m b i where
ikadub [295]
(missing part of your question):
when we have K = 1 x 10^-2 and [A] = 2 M & [B] = 3M & m= 2 & i = 1
So when the rate = K[A]^m [B]^i
and when we have m + i = 3 so the order of this reaction is 3 So the unit of K is L^2.mol^-2S^-1
So by substitution:
∴ the rate = (1x 10 ^-2 L^-2.mol^-2S^-1)*(2 mol.L^-1)^2*(3mol.L^-1)
                 = 0.12 mol.L^-1.S^-1
6 0
3 years ago
Other questions:
  • Question 1: Should acid precipitation be a concern for the new age environmentalist?
    15·1 answer
  • Why does an egg sink in fresh water but float in salt water??
    13·1 answer
  • A compound is found to contain 64.80% carbon. 13.62% hydrogen. And 21.58% oxygen by weight. What is the empirical formula for th
    8·2 answers
  • According to Newton's third law, forces come in pairs. There is_____and an equal and opposite_____.
    9·1 answer
  • Which of the following statements applies to a nuclear fission reaction?
    6·1 answer
  • What is Molecule made off?<br><br>a) Electrons<br>b) Protons<br>c) Atoms<br>d) Nuclei​
    11·2 answers
  • 1. How many moles of iron is needed to react with sulfur in order to produce 8.6 moles
    13·1 answer
  • Question 5 of 10
    9·1 answer
  • Electron orbitals or shells are also called and abbreviated as?​
    10·1 answer
  • NEED HELP PLEASE HURRY
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!