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Doss [256]
2 years ago
11

How to make 0.01 Molar solution in 30 ml of water

Chemistry
1 answer:
Leviafan [203]2 years ago
4 0

Answer:

You see the concentration decreased ten fold, from 1 M to 0.1 M.

You can simply increase the volume by ten times.

For example

If you have 250 mL of 1 molar HCl, you can add distilled water upto 2500 mL. Now the concentration is 0.1 molar.

If you want to use the serial dilution method, you can use the C1V1=C2V2 equation.

C1 = starting concentration.

C2 = final concentration.

V is for volume.

So let's say you have 500 mL of 1 M HCl and you only want 50 mL of 0.1 M HCl.

1 M x V1 = 0.1 M x 50 mL

V1 = 5 mL

So you take 5 mL of the original (stock) solution and dilute it up to 50 mL. Then you have 50 mL of 0.1 M HCl.

Explanation:

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What is the mass in grams of 358 mL of ethylene glycol?
frez [133]
The density of ethylene glycol is: D = 1.11 g/mL
D = m / V
and V = 358 mL
m = D * V
m = 1.11 g/mL * 358 mL
m = 397.38 g
Answer:
Mass is 397.38 g. 
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3 years ago
7 Which physical characteristic of a solution may
Nuetrik [128]

Answer:

2= its color

Explanation:

Transition elements are present in the middle of periodic table. These are d-block elements.

These are 38 elements.

All transition elements have partially filled d orbitals.

They showed color in compound because of d-d transition.

During the d-d transition electron absorbed the energy and emit the reminder energy. The emission is usually in the form of color light.

The color of ion is complementary to the absorbed color.

The transition elements are used as a catalyst in industries such as polymer, petroleum industries.

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5 0
2 years ago
How to calculate the number of moles
babunello [35]

Answer:

1. The formula for the number of moles formula is expressed as.

2. Given.

3. Number of moles formula is.

4. Number of moles = Mass of substance / Mass of one mole.

5. Number of moles = 95 / 86.94.

6 0
3 years ago
2HgCl2(aq) + C2O42–(aq) → 2Cl–(aq) +2CO2(g) + Hg2Cl2(s)
alexgriva [62]

Explanation:

Expression for rate of the given reaction is as follows.

             Rate = k[HgCl_{2}]x [C_{2}O^{2-}_{4}]y[/tex]

Therefore, the reaction equations by putting the given values will be as follows.

       1.8 \times 10^{-5} = k[0.105]x [0.15]y ............. (1)

       7.2 \times 10^{-5} = k [0.105]x [0.30]y ........... (2)

       3.6 \times 10^{-5} = k [0.0525]x [0.30]y ............ (3)

Now, solving equations (1) and (2) we get the value of y = 2. Therefore, by solving equation (2) and (3)  we get the value of x = 1.

Therefore, expression for rate of the reaction is as follows.

     Rate = k[HgCl_{2}]x [C_{2}O^{2-}_{4}]y

          Rate = k [HgCl2]1 [C_{2}O^{-2}_{4}]2

Hence, total order = 1 + 2 = 3

According to equation (1),

               1.8 \times 10^{-5} = k[0.105]x [0.15]y  

            1.8 \times 10^{-5} = k [0.105]1 [0.15]2  

                      k = 7.6 \times 10^{-3} M^{-2} min^{-1}  

Thus, we can conclude that rate constant for the given reaction is 7.6 \times 10^{-3} M^{-2} min^{-1}.

8 0
3 years ago
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