What causes the particles within the nucleus of an atom to bond together? Question 12 options: electromagnetism gravity weak nuc
2 answers:
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Answer:
193.4 J/K
Explanation:
For a closed system, the entropy is given as the natural logarithm of microstates.
The number of particles ( grains of sand ) N = 28
The number of boxes ( compartments ) M = 1000
Entropy is the logarithm of number of microstates
But the number of microstates is given by
Answer:
Explanation:
Given the following data;
Mass of child = 23 kg
Mass of bike = 5.5 kg
Velocity = 4.5 m/s
Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.
Mathematically, momentum is given by the formula;
To find the momentum of each of them;
I. Momentum of the child
Momentum C = mass * velocity
Momentum C = 23 * 4.5
Momentum C = 103.5 Kgm/s
II. Momentum of the bike
Momentum B = mass * velocity
Momentum B = 5.5 * 4.5
Momentum B = 24.75 Kgm/s
Hence, we can deduce from the calculations that the momentum of the child is greater than that of the bike because of the higher mass possessed by the child.
Hi there!
We can use Biot-Savart's Law for a moving particle:
B = Magnetic field strength (T)
v = velocity of electron (0.130c = 3.9 × 10⁷ m/s)
q = charge of particle (1.6 × 10⁻¹⁹ C)
μ₀ = Permeability of free space (4π × 10⁻⁷ Tm/A)
r = distance from particle (2.10 μm)
There is a cross product between the velocity vector and the radius vector (not a quantity, but specifies a direction). We can write this as:
Where 'θ' is the angle between the velocity and radius vectors.
a)
To find the angle between the velocity and radius vector, we find the complementary angle:
θ = 90° - 60° = 30°
Plugging 'θ' into the equation along with our other values:
b)
Repeat the same process. The angle between the velocity and radius vector is 150°, and its sine value is the same as that of sin(30°). So, the particle's produced field will be the same as that of part A.
c)
In this instance, the radius vector and the velocity vector are perpendicular so
'θ' = 90°.
d)
This point is ALONG the velocity vector, so there is no magnetic field produced at this point.
Aka, the radius and velocity vectors are parallel, and since sin(0) = 0, there is no magnetic field at this point.