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Marizza181 [45]
3 years ago
6

What causes the particles within the nucleus of an atom to bond together? Question 12 options: electromagnetism gravity weak nuc

lear force strong nuclear force
Physics
2 answers:
monitta3 years ago
4 0

Answer:

Strong nuclear force

Explanation:

The particles in the atom's nucleus bond together because there is a strong nuclear force between the protons and neutrons that attracts them to each other and binds together the nucleus.

Varvara68 [4.7K]3 years ago
4 0
The answer is a strong nuclear force

Reason why: The particles bond together because of the strong nuclear force between the neurons and protons
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If the radio waves transmitted by a radio station have a frequency of 76.5 mhz, what is the wavelength of the waves, in meters?
____ [38]
Given: Velocity of light    c = 3.00 x 10⁸ m/s

Frequency f = 7.65 x 10⁷/s

Required: Wavelength λ = ?

Formula:  λ = c/f

λ = 3.00 x 10⁸ m/s/7.65 x 10⁷/s

λ = 3.92 m
3 0
3 years ago
Car a with mass 1,783 kg collides with stationary 1600 kg car b. they become locked together after the collision and move with s
ValentinkaMS [17]

The initial speed of car A is 15.18 m/s.

Momentum is defined as mass in motion. If there are two objects (the two objects in motion or only one object in motion and the other in stationary) that collide and no other forces work in the system, the law of momentum conservation applies in the system.

p=p'

pa+pb = pa'+pb'

(ma×va) + (mb×vb) = (ma×va') + (mb×vb')

  • ma = mass of object A (kg) = 1,783 kg
  • mb = mass of object B (kg) = 1,600 kg
  • va = speed of object A before collides (m/s)
  • va' = speed of object A after collides (m/s) = 8 m/s
  • vb = speed of object B before collides (m/s) = 0 m/s
  • vb' = speed of object B after collides (m/s) = 8 m/s
  • p = momentum before collision (Ns)
  • p' = momentum after collision (Ns)

(ma×va) + (mb×vb) = (ma×va') + (mb×vb')

(1,783×va) + (1,600×0) = (1,783×8) + (1,600×8)

(1,783×va) + 0 = 14,264+12,800

(1,783×va) = 27,064

va \:=\: \frac{27,064}{1.783}

va = 15.18 m/s

Learn more about The law of momentum conservation here: brainly.com/question/7538238

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3 0
1 year ago
Use the passage to answer the question.
Studentka2010 [4]

This is not something that waves do because they need a medium to travel through, while particles do not.

<h3>How light travels in space?</h3>

A light travels without any medium while on the other hand, a medium is required for sound waves to move from oe place to another. Sound is a mechanical wave that cannot travel through a vacuum.

So we can conclude that electromagnetic waves like light do not require medium for its propagation.

Learn more about light here: brainly.com/question/19697218

3 0
2 years ago
An air-track glider undergoes a perfectly inelastic collision with an identical glider that is initially at rest. what fraction
Allisa [31]

In this collision, 1/2 of the initial kinetic energy of the first glider is converted into thermal energy.

<h3>In plain English, what is kinetic energy?</h3>

An object's strength as a result ofstrength an object has as a result or motion is known as kinetic energy. Toorder to accelerate an object, a force must be applied. Applying force requires effort on our part. When the work is done, power is transported to the thing, which causes it to move at the athe new, constant pace.

<h3>What does kinetic energy mean, or what are some instances?</h3>

The motion energy is known as kinetic energy, and it is manifested when a particle, object, or group if particles moves. Any moving object uses kinetic energy, including people walking, baseballs being thrown, food falling from tables, and charged particles in electric fields.

brainly.com/question/15764612

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8 0
1 year ago
Two thin rectangular sheets (0.16 m x 0.44 m) are identical. In the first sheet the axis of rotation lies along the 0.16-m side,
malfutka [58]

Answer:

t'=1.124s

Explanation:

I_b*a_b=I_a*a_a

a_a=\frac{w_f}{t'}

a_b=\frac{w_f}{t}

I_b*\frac{w_f}{t}=I_a*\frac{w_f}{t'}

I_b*\frac{1}{t}=I_a*\frac{1}{t'}

I=\frac{1}{3}*M*r^2

I_a=\frac{1}{3}*M*r_a^2

I_b=\frac{1}{3}*M*r_b^2

\frac{1}{3}*M*r_b^2*\frac{1}{t}=\frac{1}{3}*M*r_a^2*\frac{1}{t'}

t'=(\frac{r_a}{r_b})^2 *t

t'=(\frac{0.16m}{0.44m})^2*t

t'=\frac{16}{121}*8.5s

t'=1.124s

7 0
3 years ago
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