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sp2606 [1]
3 years ago
15

The law of conservation of energy states:

Physics
1 answer:
Alborosie3 years ago
6 0

Answer:

In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time. ... For instance, chemical energy is converted to kinetic energy when a stick of dynamite explodes.

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5. Based on the data collected by the students, what is the tangential velocity of
malfutka [58]

The tangential velocity of the ball is 0.63 m/s.

<h3>What is tangential speed?</h3>

Tangential speed is the linear component of the speed of any object moving along a circular path.

v = ωr

where;

  • v is the tangential speed
  • ω is the angular speed (rad/s)
  • r is the radius of the circle

At a given radius of the circle = 0.3 m

Let the number of revolution per min = 20 rev/min

\omega = 20 \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1 \min}{60 \ s} = 2.1 \ rad/s

v = ωr

v = 2.1 x 0.3

v = 0.63 m/s

Thus, the tangential velocity of the ball is 0.63 m/s.

Learn more about tangential velocity here: brainly.com/question/25780931

8 0
2 years ago
Particle motion in surface waves is __________ motion.
Readme [11.4K]

Answer:

A combination of longitudinal & transverse

Explanation:

6 0
3 years ago
Read 2 more answers
A car is going through a dip in the road whose curvature approximates a circle of radius 200 m. At what velocity will the occupa
boyakko [2]

Answer:

Explanation:

The solution along with the diagram can be found in the attachment. Feel free to raise doubts.

4 0
3 years ago
Use the diagram below modeling a football kicked from a horizontal surface B
djyliett [7]
B is the correct one
5 0
3 years ago
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a compound is 24.7% calcium, 1.2% hydrogen, 14.8% carbon, and 59.3% oxygen. write the empirical formula and name the compound.
Tema [17]
For simplicity, assume that the total mass of the compound is 100 g.

Therefore, by mass
Ca = 24.7 g, H = 1.2 g, C = 14.8 g, and O = 59.3 g

Converting these to moles

Mol = mass*1/atomic mass
Ca = 24.7*1/40.078 =0.6163 mol Ca
H = 1.2*1/1.01 = 1.1881 mol H
C = 14.8*1/12.01 = 1.2323 mol C
O = 59.3/16 = 3.7062 mol O

Next, divide all the mols by the smallest value obtained.

Ca: 0.6163/0.6163 = 1 mol Ca
H: 1.1881/0.6163 = 2 mol H
C: 1.2323/0.6163 = 2mol C
O: 3.7062/0.6163 = 6 mol O

Therefore, empirical formula of the compound is

CaH2C2O6

This compound is referred to as Calcium Bicarbonate
8 0
3 years ago
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