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2 years ago

Based on the mass and speed data, which object will have the greatest amount of kinetic energy

Physics

2 answers:

Masteriza [31]2 years ago

6 0

Answer:

The object with more mass and steepest ground will have more kinetic energy.

Explanation:

This answer is because gravity pulls harder on objects with more mass. The steeper the ground is and the more mass an object has, the faster it will go. The more an object is moving, the more kinetic energy it has.

I hope this helps, that you have a good rest of your day, and that you get a good score.

Alexus [3.1K]2 years ago

5 0

The objects will have to be listed

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A 7 cm thick and 20 cm long wedge is used to pierce a 3cm long log of diameter 20cm what is the velocity ratio of the wedge

stiks02 [169]

Answer:

The velocity ratio of the wedge is 0.15

Explanation:

Use the following formula to calculate the velocity ratio

Velocity Ratio = Distance Moved by effort / Distance moved by Load

Where

Distance Moved by effort = 3cm

Distance moved by Load = 20 cm

Placing values in the formula

Velocity Ratio = 3cm / 20 cm

Velocity Ratio = 0.15

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3 years ago

The point on the graph that lies on the y-axis (vertical axis) is called the y-intercept. What does the y-intercept tell you abo

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Answer:

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Explanation:

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4 years ago

What is the mass of a 7.0 kilogram bowling ball on the surface of the moon?

babunello [35]

Answer:

1.16kg is the answer. Hope this helped

Explanation:

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2 years ago

Which of the following is not an example of a chemical reaction? Rust, Photosynthesis, Melting Ice, Heat from Fire?

FinnZ [79.3K]

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3 years ago

Read 2 more answers

The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 22

alexgriva [62]

1) The law of motion of the projectile is
$h(t) = 2+22.5 t-4.9 t^2$
To find the velocity, we should compute the derivative of h(t):
$v(t)=h'(t)=22.5-2\cdot 4.9t=22.5-9.8t$
So now we can calculate the speed at t=2 s and t=4 s:
$v(2.0s)=22.5-9.8\cdot2.0 =2.9 m/s$
$v(4.0s)=22.5-9.8\cdot 4.0s=-16.7 m/s$
The negative sign in the second speed means the projectile has already reached its maximum height and it is now going downward.

2) The projectile reaches its maximum height when the speed is equal to zero:
$v(t)=0$
So we have
$22.5-9.8 t=0$
And solving this we find
$t=2.30 s$

3) To find the maximum height, we take h(t) and we just replace t with the time at which the projectile reaches the maximum height, i.e. t=2.30 s:
$h(2.30 s)=2+22.5\cdot 2.30 -4.9 \cdot (2.30s)^2 = 27.83 m$

4) The time at which the projectile hits the ground is the time at which the height is zero: h(t)=0. So, this translates into
$2+22.5t -4.9 t^2 = 0$
This is a second-order equation, and if we solve it we get two solutions: the first solution is negative, so we can ignore it since it's physically meaningless; the second solution is
$t=4.68 s$
And this is the time at which the projectile hits the ground.

5) The velocity of the projectile when it hits the ground is the velocity at time t=4.68 s:
$v(4.68 s)=22.5-9.8\cdot 4.68 =-23.36 m/s$
with negative sign, because it is directed downward.

8 0

4 years ago