Answer:
i don't know this one!
Step-by-step explanation:
sorry!
Answer:
(a) 0.119
(b) 0.1699
Solution:
As per the question:
Mean of the emission,
million ponds/day
Standard deviation,
million ponds/day
Now,
(a) The probability for the water pollution to be at least 15 million pounds/day:


= 1 - P(Z < 1.178)
Using the Z score table:
= 1 - 0.881 = 0.119
The required probability is 0.119
(b) The probability when the water pollution is in between 6.2 and 9.3 million pounds/day:



P(Z < - 0.86) - P(Z < - 1.96)
Now, using teh Z score table:
0.1949 - 0.025 = 0.1699
Answer:
Step-by-step explanation:
The method applied in this scenario is called simple random sampling. A sample of 100 customers is chosen from a larger population of customers and each customer has the same chance of being selected for the survey at any given time. Also, the chance of selecting 100 customers from each store is the same during the sampling process. The order of sampling at each store does not follow a certain order, thus, It is different from systematic random sampling.
<span>180 degrese or some thing flat</span>
X - the number of loads by land carriers,
y - the number of loads by air carriers;
The system of inequalities:
x + y ≤ 150
2,000 x + 1,250 y ≤ 180,000