Solar heating is the system composed of a fluid system to move the heat from the collector to its point of usage and a reservoir to stock the heat
<u>Explanation:</u>
The options given here like coal burning uses solid material as the source to heat and to generate energy. Similarly, nuclear power also requires solid particles like atoms or neutrons to strike the moderators forming energy.
In both of these cases, fluid system is present but it is used completely as coolant and to maintain the temperature. Thus, the remaining system that is solar heating has been done for water tanks where the fluid as water is used to move the heat from its collector to its point of usage. Even in solar system it is used as reservoir to stock the heat.
Explanation:
Given:![F=m\ddot{x}=Fe^{-\frac{t}{T}}](https://tex.z-dn.net/?f=F%3Dm%5Cddot%7Bx%7D%3DFe%5E%7B-%5Cfrac%7Bt%7D%7BT%7D%7D)
Solving for
:
![\ddot{x}=\frac{F}{m}e^{-\sqrt{\frac{F}{m} } t}](https://tex.z-dn.net/?f=%5Cddot%7Bx%7D%3D%5Cfrac%7BF%7D%7Bm%7De%5E%7B-%5Csqrt%7B%5Cfrac%7BF%7D%7Bm%7D%20%7D%20t%7D)
where:
![T=\sqrt{\frac{m}{F}}](https://tex.z-dn.net/?f=T%3D%5Csqrt%7B%5Cfrac%7Bm%7D%7BF%7D%7D)
Integrating to get
with initial conditions
:
![\dot{x}=\sqrt{\frac{F}{m}}-\sqrt{\frac{F}{m}} e^{-\sqrt{\frac{F}{m}} t}](https://tex.z-dn.net/?f=%5Cdot%7Bx%7D%3D%5Csqrt%7B%5Cfrac%7BF%7D%7Bm%7D%7D-%5Csqrt%7B%5Cfrac%7BF%7D%7Bm%7D%7D%20e%5E%7B-%5Csqrt%7B%5Cfrac%7BF%7D%7Bm%7D%7D%20t%7D)
Integrating to get x with initial conditions x(0) = 0:
![x=-1+\sqrt{\frac{F}{m}} t+e^{-\sqrt{\frac{F}{m}}t}](https://tex.z-dn.net/?f=x%3D-1%2B%5Csqrt%7B%5Cfrac%7BF%7D%7Bm%7D%7D%20t%2Be%5E%7B-%5Csqrt%7B%5Cfrac%7BF%7D%7Bm%7D%7Dt%7D)
When t=T:
![x=-1+\sqrt{\frac{F}{m}}\sqrt{\frac{m}{F}}+e^{-\sqrt{\frac{F}{m}}\sqrt{\frac{m}{F}}}=\frac{1}{e}](https://tex.z-dn.net/?f=x%3D-1%2B%5Csqrt%7B%5Cfrac%7BF%7D%7Bm%7D%7D%5Csqrt%7B%5Cfrac%7Bm%7D%7BF%7D%7D%2Be%5E%7B-%5Csqrt%7B%5Cfrac%7BF%7D%7Bm%7D%7D%5Csqrt%7B%5Cfrac%7Bm%7D%7BF%7D%7D%7D%3D%5Cfrac%7B1%7D%7Be%7D)
![\dot{x}=\sqrt{\frac{F}{m}}-\sqrt{\frac{F}{m}} e^{-\sqrt{\frac{F}{m}}\sqrt{\frac{m}{F}}}=\sqrt{\frac{F}{m}}(1-\frac{1}{e})](https://tex.z-dn.net/?f=%5Cdot%7Bx%7D%3D%5Csqrt%7B%5Cfrac%7BF%7D%7Bm%7D%7D-%5Csqrt%7B%5Cfrac%7BF%7D%7Bm%7D%7D%20e%5E%7B-%5Csqrt%7B%5Cfrac%7BF%7D%7Bm%7D%7D%5Csqrt%7B%5Cfrac%7Bm%7D%7BF%7D%7D%7D%3D%5Csqrt%7B%5Cfrac%7BF%7D%7Bm%7D%7D%281-%5Cfrac%7B1%7D%7Be%7D%29)
It is customary to work in SI units.
Calculate the volume of the concrete.
V = 3.7*2.1*5.8 cm³ = 45.066 cm³ = 45.066 x 10 ⁻⁶ m³
The mass is 43.8 g = 43.8 x 10⁻³ kg
The density is mass/volume.
Density = (43.8 x 10⁻³ kg)/(45.066 x 10⁻⁶ m³) = 971.9 kg/m³
Answer: 971.9 kg/m³
The gravitational force is inversely proportional to the
square of the distance between their centers. So the
force is greatest when the distance is zero.
Answer:
A I think
Explanation:
because what is the most frequency a because it has more frequency I think I'm not that sure