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Ghella [55]
3 years ago
13

An overhead projector lens is

Physics
1 answer:
Inessa [10]3 years ago
6 0

Answer: 34.9 cm

Explanation:

You are given the following parameters;

Object distance U = 32 cm

Magnification M = - 12.0

According to formula for magnification;

M = V/U

Where V = image distance.

Substitute V and M into the formula

-12 = V/32

Cross multiply

V = -12 × 32

V = - 384

You can use the formula

1/f = 1/V + 1/U

Where f = focal length

Substitute V and U into the formula

1/f = - 1/384 + 1/32

Find the lowest common factor of the denominator at Left hand side

1/f = ( -1 + 12 ) / 384

1/f = 11/384

Reciprocate both sides

F = 384/11

F = 34.9 cm

He should therefore use the focal length of 34.9 cm

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i) E = 269 [MJ]    ii)v = 116 [m/s]

Explanation:

This is a problem that encompasses the work and principle of energy conservation.

In this way, we establish the equation for the principle of conservation and energy.

i)

E_{k1}+W_{1-2}=E_{k2}\\where:\\E_{k1}= kinetic energy at moment 1\\W_{1-2}= work between moments 1 and 2.\\E_{k2}= kinetic energy at moment 2.

W_{1-2}= (F*d) - (m*g*h)\\W_{1-2}=(500000*2.5*10^3)-(40000*9.81*2.5*10^3)\\W_{1-2}= 269*10^6[J] or 269 [MJ]

At that point the speed 1 is equal to zero, since the maximum height achieved was 2.5 [km]. So this calculated work corresponds to the energy of the rocket.

Er = 269*10^6[J]

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